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3 years ago

2. How can you determine if an acid is binary when given the formula?

Chemistry

1 answer:

AysviL [449]3 years ago

7 0

Explanation:

Binary acids are molecular compounds that consists of two components.

The components are Hydrogen and a non metal. Examples of binary acids include; HCl, HF etc.

The way to identify binary acids is to spot the hydrogen and the non metal.

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Students experiment with the flow of

OleMash [197]

Rubber is not very good at conducting electricity. This is because rubber makes it difficult for electrons to flow between atoms, due to rubber having tightly packed electrons. Materials like rubber are known as insulators.
Conductors are the opposite, they conduct electricity very well. Examples of conductors are metal, which is why metal is used in wires.
Since rubber is not a conductor, answer choice B can be eliminated. This can also eliminate answer choice D, since insulators like rubber don't allow electricity to easily flow.
While rubber gloves keep our hands dry, there are no liquids involved in this experiment and this is not the main reason for using rubber gloves. This eliminates answer choice C.

The answer is A. rubber gloves are insulators.
The teacher instructs the students to wear rubber gloves to prevent them from getting an electric shock.

Answer:
A. rubber gloves are insulators

Hope this helps!

5 0

3 years ago

Read 2 more answers

Describe how you would prepare approximately 2 l of 0.050 0 m boric acid, b(oh)3.

Elenna [48]

The given concentration of boric acid = 0.0500 M

Required volume of the solution = 2 L

Molarity is the moles of solute present per liter solution. So 0.0500 M boric acid has 0.0500 mol boric acid present in 1 L solution.

Calculating the moles of 0.0500 M boric acid present in 2 L solution:

$2 L * \frac{0.0500 mol B(OH)_{3} }{1 L} = 0.100 mol B(OH)_{3}$

Converting moles of boric acid to mass:

$0.100 mol B(OH)_{3} * \frac{61.83 g}{mol B(OH)_{3}} = 6.183 g$

Therefore, 6.183 g boric acid when dissolved and made up to 2 L with distilled water gives 0.0500 M solution.

5 0

3 years ago

IF A CAPPED GLASS BOTTLE IS THROWN INTO A FIRE, WHAT WILL HAPPEN TO THE BOTTLE AND WHY?

ArbitrLikvidat [17]

Answer:

it will explode (not intensely) there is some oxygen in the bottle so the cap would pop off violently, the longer it stays in the fire the more energy is being pent up.

Explanation:

8 0

3 years ago

Read 2 more answers

I will give brainliest!!!!!

creativ13 [48]

Answer:

1. equator

2. west to east

3. equator

4. north to south

5. hemisphears

Explanation:

Mark as brainliest please

4 0

3 years ago

The wall of an industrial furnace is constructed from 0.15-m-thick, fireclay brick having a thermal conductivity of LZ W/m.K. Me

aliya0001 [1]

Answer:

The rate of heat loss through the wall is 1700 watts.

Explanation:

The complete statement of the problem is:

<em>The wall of an industrial furnace is constructed from 0.15-m-thick, fireclay brick having a thermal conductivity of 1.7 W/m·K. Measurements made during steady state operation reveal temperatures of 1400 and 1150 K at the inner and outer sur- faces, respectively. What is the rate of heat loss through a wall that is 0.5 m by 1.2 m on a side?</em>

Given that wall of the industrial furnace is under steady conditions of heat transfer and whose configuration is a flat element, we use the equation of conductive heat transfer rate ( $\dot Q$ ), measured in watts:

$\dot Q = \frac{k\cdot w\cdot h}{l}\cdot (T_{i}-T_{o})$

Where:

$k$ - Thermal conductivity, measured in watts per meter-Kelvin.

$w$ - Width of the wall, measured in meters.

$h$ - Height of the wall, measured in meters.

$l$ - Thickness of the wall, measured in meters.

$T_{i}$ - Inner surface temperature, measured in Kelvin.

$T_{o}$ - Outer surface temperature, measured in Kelvin.

If we know that $k = 1.7 \,\frac{W}{m\cdot K}$ , $w = 1.2\,m$ , $h = 0.5\,m$ , $l = 0.15\,m$ , $T_{i} = 1400\,K$ and $T_{o} = 1150\,K$ , the steady state heat transfer is:

$\dot Q = \left[\frac{\left(1.7\,\frac{W}{m\cdot K} \right)\cdot (1.2\,m)\cdot (0.5\,m)}{0.15\,m} \right]\cdot (1400\,K-1150\,K)$

$\dot Q = 1700\,W$

The rate of heat loss through the wall is 1700 watts.

3 0

3 years ago