Question

Calculating molarity using solute moles A chemist prepares a solution of sodium chloride (NaCl) by measuring out 6.89 mol of sodium chloride into a 200 ml volumetric flask and filling the the mark with water. Calculate the concentration in mol/L of the chemist's sodium chloride solution. Round your answer to 3 significant digits. X 5 ? Explanation Check

Answer 1

Answer: Concentration of the chemist's sodium chloride solution is 34.4 mol/L.

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

$Molarity=\frac{n\times 1000}{V_s}$

where,

n= moles of solute

$V_s$ = volume of solution in ml

Given : moles of $NaCl$ = 6.89

volume of solution = 200 ml

Putting in the values we get:

$Molarity=\frac{6.89\times 1000}{200}=34.4mol/L$

Thus the concentration of the chemist's sodium chloride solution is 34.4 mol/L.