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3 years ago

7

How are heterogeneous and homogeneous mixtures separated?

1 answer:

Andre45 [30]3 years ago

8 0

Answer:

Explanation:

In heterogeneous mixtures, two or more ingredients (or phases, regions with uniform composition and properties) intermingle, but remain physically separate. Often it is possible to separate the original ingredients by physical means, such as filtering.

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Can anybody plz answer

Lelechka [254]

Answer: heat

Other indicators: color change, odor, gas, temperature change.

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3 years ago

Blood samples for research or medical tests sometimes have heparin added. Why is this done?

alina1380 [7]

It is essential for accurate results that the correct volume of blood is sampled to achieve a correct concentration (and dilution, if liquid heparin is used), and that blood and anticoagulant are well mixed immediately after sampling.

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3 years ago

The half life of radon-222 is 3.8 days. How Much of a 100g sample is left after 15.2 days

professor190 [17]

Answer:

6.2 g

Explanation:

In a first-order decay, the formula for the amount remaining after <em>n</em> half-lives is

$N = \frac{N_{0}}{2^{n}}$

where

<em>N</em>₀ and <em>N</em> are the initial and final amounts of the substance

1. Calculate the <em>number of half-lives</em>.

If $t_{\frac{1}{2}} = \text{3.8 da}$

$n = \frac{t}{t_{\frac{1}{2}}} = \frac{\text{15.2 da}}{\text{3.8 da}}= \text{4.0}$

2. Calculate the <em>final mass</em> of the substance.

$\text{N} = \frac{\text{100 g}}{2^{4.0}} = \frac{\text{100 g}}{16} = \text{6.2 g}$

4 0

3 years ago

Can someone please help

oksian1 [2.3K]

Answer:

Even ur best Friend Can you to have red flag feeling

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3 years ago

Mount Everest rises to a height of 8,850 m above sea level. At a base camp on the mountain the atmospheric pressure is measured

yan [13]

Answer:

Water will boil at $76^{0}\textrm{C}$ .

Explanation:

According to clausius-clapeyron equation for liquid-vapor equilibrium:

$ln(\frac{P_{2}}{P_{1}})=\frac{-\Delta H_{vap}^{0}}{R}[\frac{1}{T_{2}}-\frac{1}{T_{1}}]$

where, $P_{1}$ and $P_{2}$ are vapor pressures of liquid at $T_{1}$ (in kelvin) and $T_{2}$ (in kelvin) temperatures respectively.

Here, $P_{1}$ = 760.0 mm Hg, $T_{1}$ = 373 K, $P_{2}$ = 314.0 mm Hg

Plug-in all the given values in the above equation:

$ln(\frac{314.0}{760.0})=\frac{-40.7\times 10^{3}\frac{J}{mol}}{8.314\frac{J}{mol.K}}\times [\frac{1}{T_{2}}-\frac{1}{373K}]$

or, $T_{2}=349 K$

So, $T_{2}=349K=(349-273)^{0}\textrm{C}=76^{0}\textrm{C}$

Hence, at base camp, water will boil at $76^{0}\textrm{C}$

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3 years ago