There are approximately 160 grams in 1 mol of Fe2O3 molecules. Therefore, there would be 79/160= 0.49375 mols of Fe2O3 molecules in 79 grams. There are 5 atoms in total for each molecule of Fe2O3, therefore 79/160 * 5 = 79/32 = 2.46875 mols of atoms.
The mass for of aluminum that is produced by the decomposition of 5.0 Kg Al2O3 is 2647 g or 2.647 Kg
calculation
Write the equation for decomposition of Al2O3
Al2O3 = 2Al + 3 O2
find the moles of Al2O3 = mass/molar mass
convert 5 Kg to g = 5 x1000 = 5000 grams
molar mass of Al2O3 = 27 x2 + 16 x3 = 102 g/mol
moles =5000 g/ 102 g/mol = 49.0196 moles
by use of mole ratio between Al2O3 to Al which is 1:2 the moles of Al = 49.0196 x2 =98.0392 moles
mass of Al = moles x molar mass
= 98.0392 moles x 27g/mol = 2647 grams or 2647/1000 = 2.647 Kg
The correct answer is IE decreases down the group.
On moving down the group, the size of the element increases due to the increase in the number of shells. The element with smallest size has less the attraction of the nucleus on the valance electron. It needs more energy to remove an electron from its valance shell. Hence, the IE decreases down the group.
Why does ionization energy increase down the group but decreases going across a period?
Because there are more protons with time, the ionization energy rises. As a result, there will be more attraction because the nuclear charge has increased.
Even if there is stronger attraction, one should be aware that the shielding effect and distance from the nucleus remain largely constant. The same primary quantum shell contains all of the valence electrons, which explains this.
Therefore, while distance from the nucleus and the shielding effect stay fairly constant, an increase in nuclear charge causes an increase in attraction and increases the energy required to remove an electron.
The ionization energy drops with each group. This is because the outside electrons acting as a shield or screen for the nucleus make the attraction between them weaker and make it easier for them to be withdrawn.
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Answer:
Conformational isomers
Explanation:
Conformational isomers are temporarily different shapes of the same molecule and for this reason are not classified as isomers in some textbooks.
In the herbicide linuron whose structure is shown in the image attached, there are four pi bonds.
A pi bond is formed by a sideways overlap of atomic orbitals. A sigma bond is formed by an end to end or head to head overlap of atomic orbitals. Pi bonds lead to the occurrence of multiple bonds in the molecule.
In the herbicide linuron whose structure is shown in the image attached to this answer, there are four pi bonds which are easily spotted as double bonds in the structure.
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