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Nadusha1986 [10]
2 years ago
11

A certain shade of blue has a frequency of 7.03 × 1014 Hz. What is the energy of exactly one photon of this light?

Chemistry
1 answer:
Vsevolod [243]2 years ago
7 0
<span>4.66 x 10^-19 Joules The energy of a photon is E=hf Where E = Energy h = Planck's constant (6.62607004Ă—10â’34 J s) f = frequency of photon. So plug in the known values E = 6.62607004Ă—10â’34 J s * 7.03 x 10^14 1/s E = 4.65812724x10^-19 J Since we only have 3 significant figures, the rounded result is E = 4.66x10^-19 J</span>
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100 POINTS! Final Honor Activity Question
castortr0y [4]

The change in temperature had the greatest effect at changing the volume of the balloon.

<h3>What are the gas laws?</h3>

The gas laws are used to describe the parameters that has to do with gases.

Given that;

P1 = 98.5 kPa

T1 = 18oC or 291 K

V1 =  74.0 dm3

P2 =  7.0 kPa

V2 = ?

T2 = 18oC or 291 K

P1V1/T1 = P2V2/T2

P1V1T2 =P2V2T1

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V2 = V1T2/T1

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The change in temperature had the greatest effect at changing the volume of the balloon.

Given that

V1 =  100 cm^3

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P1 = 1.01 * 10^5 Pa

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V2 = 3.14 * 10^10 cm^3

Learn more about gas laws:brainly.com/question/12669509

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Mass of O_2=moles\times {\text {Molar mass}}=14moles\times 32g/mol=448g

Thus 448g of O_2 will be required to completely react with 784g moles of CO(g) during this reaction.

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