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3 years ago

11

65 ml of a 1.3 m solution is dilluted to a total volume of 208 ml. a 104 ml portion of that solution is dilluted by adding 109 m

l of water. what is the concentration? assume the volumes are additive

1 answer:

storchak [24]3 years ago

8 0

65ml x 1.3 molar = 0.0845 moles solution #1

0.0845 moles / .208 L = 0.4 M

0.4M × 104 ml / 213 ml = .20 M after sig figs

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Read 2 more answers

Please help with #2 and #3

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Hello there!

2. In this case, we can evidence the problem by which volume and temperature are involved, so the Charles' law is applied to:

$\frac{V_2}{T_2}=\frac{V_1}{T_1}$

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Best regards!

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