Question

65 ml of a 1.3 m solution is dilluted to a total volume of 208 ml. a 104 ml portion of that solution is dilluted by adding 109 ml of water. what is the concentration? assume the volumes are additive ​

Answer 1

65ml x 1.3 molar = 0.0845 moles solution #1

0.0845 moles / .208 L = 0.4 M

0.4M × 104 ml / 213 ml = .20 M after sig figs