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3 years ago

14

The point (-4,-5) is rotated 270 degrees clockwise

2 answers:

Veronika [31]3 years ago

6 0

Answer:

(5,-4)

Step-by-step explanation: (x,y)--->(y,-x)=(-4,-5)--->(5,-4). I had a similar question to this one and I put my answer like that and I got it right, hope this helps!

Alex73 [517]3 years ago

3 0

Answer:

90 degrees

Step-by-step explanation:

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Correctly name the following angle.

chubhunter [2.5K]

Answer: ∠EDC or ∠CDE

Step-by-step explanation:

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3 years ago

For what values (cases) of the variables the expression does not exist: <img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4y%2B

stealth61 [152]

Answer:

y = - $\frac{1}{2}$

Step-by-step explanation:

Given

$\frac{3}{4y+2}$

The denominator of the expression cannot be zero as this would make it undefined. Equating the denominator to zero and solving gives the value that y cannot be, that is

4y + 2 = 0 ( subtract 2 from both sides )

4y = - 2 ( divide both sides by 4 )

y = $\frac{-2}{4}$ = - $\frac{1}{2}$ ← excluded value

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3 years ago

X/5 +8=3 what would x be

OverLord2011 [107]

Answer: x= -25

Step-by-step explanation:

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4 years ago

Read 2 more answers

Solve x^2=18 where x is a real number

V125BC [204]

Answer:

x = ±3√2

or in decimal:

x = ±4.24

Step-by-step explanation:

x² = 18

x = ±√18

= ±√2√9

= ±3√2

6 0

3 years ago

Read 2 more answers

A Confidence interval is desired for the true average stray-load loss mu (watts) for a certain type of induction motor when the

Vaselesa [24]

Answer:

A sample size of 35 is needed.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find the width W as such

$W = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

How large must the sample size be if the width of the 95% interval for mu is to be 1.0:

We need to find n for which W = 1.

We have that $\sigma^{2} = 9$ , then $\sigma = \sqrt{\sigma^{2}} = \sqrt{9} = 3$ . So

$W = z*\frac{\sigma}{\sqrt{n}}$

$1 = 1.96*\frac{3}{\sqrt{n}}$

$\sqrt{n} = 1.96*3$

$(\sqrt{n})^2 = (1.96*3)^{2}$

$n = 34.57$

Rounding up

A sample size of 35 is needed.

3 0

3 years ago