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3 years ago

How do you solve: 4/10y+28=0

Mathematics

1 answer:

Bezzdna [24]3 years ago

3 0

Answer:

Step-by-step explanation:

$\dfrac{4}{10}y+28=0\qquad\text{subtract 28 from both sides}\\\\\dfrac{4:2}{10:2}y=-28\\\\\dfrac{2}{5}y=-28\qquad\text{multiply both sides by 5}\\\\5\!\!\!\!\diagup^1\cdot\dfrac{2}{5\!\!\!\!\diagup_1}y=-140\\\\2y=-140\qquad\text{divide both sides by 2}\\\\y=-70$

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For two triangles to be similar, the ratio of the measure of similar sides of the triangle must be equal to a constant known as a scale factor.

From the given figures, the expression that can be used to prove that the triangles are similar is as shown;

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Learn more on similar triangles here; brainly.com/question/11920446

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