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2 years ago

How do you solve: 4/10y+28=0

Mathematics

1 answer:

Bezzdna [24]2 years ago

3 0

Answer:

Step-by-step explanation:

$\dfrac{4}{10}y+28=0\qquad\text{subtract 28 from both sides}\\\\\dfrac{4:2}{10:2}y=-28\\\\\dfrac{2}{5}y=-28\qquad\text{multiply both sides by 5}\\\\5\!\!\!\!\diagup^1\cdot\dfrac{2}{5\!\!\!\!\diagup_1}y=-140\\\\2y=-140\qquad\text{divide both sides by 2}\\\\y=-70$

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PLEASE HELP ASAP <br> I need help finding the rate of change

Talja [164]

G(6)-g(2)/6-2
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50-14/6-2
36/4
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3 years ago

A) Find a particular solution to y" + 2y = e^3 + x^3. b) Find the general solution.

Reptile [31]

Answer:

a.P.I= $\frac{e^{3x}}{11}+\frac{1}{2}(x^3-3x)$

b.G.S= $C_1Cos \sqrt2 x+C_2 Sin\sqrt2 x+\frac{1}{11}e^{3x}+\frac{1}{2}(x^3-3x}$

Step-by-step explanation:

We are given that a linear differential equation

$y''+2y=e^{3x}+x^3$

We have to find the particular solution

P.I= $\frac{e^{3x}}{D^2+2}+\frac{x^3}{D^2+2}$

P.I= $\frac{e^{3x}}{3^2+2}+\frac{1}{2} x^3(1+\frac{D^2}{2})^{-2}$

P.I= $\frac{e^{3x}}{11}+\frac{1-2\frac{D^2}{4}+3\frac{D^4}{16}+...}{2}x^3$

P.I= $\frac{e^{3x}}{11}+\frac{x^3-2\frac{\cdot3\cdot 2x}{4}}{2}+0}$ (higher order terms can be neglected

P.I= $\frac{e^{3x}}{11}+\frac{1}{2}(x^3-3x)$

b.Characteristics equation

$D^2+2=0$

$D=\pm\sqrt2 i$

C.F= $C_1cos \sqrt2x+C_2 sin\sqrt2 x$

G.S=C.F+P.I

G.S= $C_1Cos \sqrt2 x+C_2 Sin\sqrt2 x+\frac{1}{11}e^{3x}+\frac{1}{2}(x^3-3x)$

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3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Harman [31]

Answer:

Step-by-step explanation:

the answer is D because the line touches the graph on the y intercept at points -4, 1, and 2

4 0

3 years ago

Read 2 more answers

Use the quadratic formula to determine the exact solutions to the equation.

lawyer [7]

Answer:

x= 2.28

or, x= 0.219

Step-by-step explanation:

2x²-5x+1 =0

a= 2, b= -5 and c= 1

x= (-b <u>+</u> √(b²-4ac))/2a

= (5 <u>+</u> √(25-8))/4

= (5 <u>+</u> √17)/4

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3 years ago

AB contains the points A(7, -11) and B (8, 17) Find the slope of a line perpendicular to AB.

lesya692 [45]

The slope of the line containing the points is 28... we need the negative reciprocal of this for the slope of line perpendicular..

So the slope would be: choice B

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2 years ago