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Ipatiy [6.2K]
3 years ago
14

CW 18 118 The following information is given to you: Cost of material per unit : Rs.200 Ordering cost : Rs.100 per order Annual

carrying cost : 10% of the average cost of material Total carrying and ordering cost (Total cost at EOQ): Rs.4,000 Required: a) Annual requirement b) EOQ​
Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
4 0
Ay yo you got this dude
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How would you write 87 as a Roman numeral?
ddd [48]

Answer:

LXXXVII

Step-by-step explanation:

L=50 X=10 V=5 I=1

So basically you need to figure out what adds up to the 87. so use L, or 50. now XXX=30. so now you have 80 so we still have 7 left over, so we can write 7 I's or a 5, (V) and two I's. We should use the V and the I. So we take one V, or 5. and two I's which together is 7. which leads us too LXXXVII. also always remember to have the biggest number first, in this case the L (50).

7 0
3 years ago
4/3C, when C=6<br> show your work here
tresset_1 [31]

4 divided by 3C

If C equals 6, then the equation now looks like 4 divided by 3(6).

3 x 6 = 18.

4 divided by 18 is .22 repeating.

This may be wrong. Check with another answer.

6 0
3 years ago
Read 2 more answers
Consider a polynomial p(x) with a degree of 9. What is the largest possible number of x-intercepts and the largest possible numb
tia_tia [17]

Answer:

The largest possible number of x intercept is 9 while the largest possible number of relative max/min is 8

Step-by-step explanation:

For any polynomial of degree n with distinct and real solutions, it can have at most n different x intercepts. This would imply it can have at most 9 distinct real solutions.

It can also have at most n-1 relative max/min in alternating order. This is best illustrated when such polynomial is sketched on a graph.

For example a quadratic expression is a polynomial of degree 2 and has at most 2 distinct solutions and 1 relative max/min.

In this question, for the polynomial, its degree (n) = 9

So it can have at most 9 x intercepts and at most 8 relative max/min.

3 0
3 years ago
6 children and 2 adults are going to the circus. Children tickets are on sale,half price of adult tickets totaling $54. How much
Anon25 [30]

Answer:

Price of 1 adult ticket is <u>$10.8</u> and Price of 1 children ticket is <u>$5.4</u>.

Step-by-step explanation:

Given:

Number of adults = 2

Number of Children = 6

Total Amount of tickets sold = $54.

We need to find the price of one children's ticket and one adult ticket.

Solution:

Let the Cost of 1 adult ticket be 'x'.

Now Given:

Children tickets are on sale,half price of adult tickets.

Cost of 1 Children ticket = \frac{1}{2}x

Total Amount is equal to Number of adults multiplied by Cost of adult ticket plus Number of Children multiplied by Cost of Children ticket.

Framing in equation for we get;

2x+\frac{1}{2}x\times 6=54\\\\2x+3x=54\\\\5x=54\\\\x=\frac{54}{5} = \$10.8

Cost of 1 adult ticket = $10.8

Cost of 1 children ticket = \frac{x}{2}=\frac{10.8}{2} = \$5.4

Hence Price of 1 adult ticket is <u>$10.8</u> and Price of 1 children ticket is <u>$5.4</u>.

7 0
3 years ago
A beverage company makes 100% cranapple juice, which is made up of
Vedmedyk [2.9K]
Answer: 54-fluid ounces
5 0
3 years ago
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