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Anarel [89]
2 years ago
13

solve for x and round to the nearest tenth. this is geometry. I will mark Brainliest. please help <3

Mathematics
1 answer:
Amiraneli [1.4K]2 years ago
5 0

Answer:

x= 41.8°

Step-by-step explanation:

use inverse trig to find x.

sin^{-1}(\frac{4}{6})=x

type this into your calculator. (make sure the mode on your calculator is degree or it won't work)

x= 41.8

Hope This Helps:)

brainliest please

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-p/3 - 8 = -3 I need the show work too
professor190 [17]

Answer:

-15

Step-by-step explanation:

-3+8-5. 5x3=15 and because it is -p it would be -15.

3 0
2 years ago
What types of numbers are undefined when they are under a radical sign? If you were dealing with the number √-1, would it be def
Misha Larkins [42]
The square root of a a negative integer is imaginary.
It would still be a negative under a square root if you multiplied it by 2, therefor it will still be imaginary, or I’m assuming as your book calls it, undefined.
2•(sqrt-1) = 2sqrt-1

If you add a number to -1 itself, specifically 1 or greater it will become a positive number or 0 assuming you just add 1. In that case it would be defined.
-1 + 1 = 0
-1 + 2 = 1

If you add a number to the entire thing “sqrt-1” it will not be defined.
(sqrt-1) + 1 = 1+ (sqrt-1)

If you subtract a number it will still have a negative under a square root, meaning it would be undefined.
(sqrt-1) + 1 = 1 + (sqrt-1)

however if you subtract a negative number from -1 itself, you end up getting a positive number or zero. (Subtracting a negative number is adding because the negative signs cancel out).
-1 - -1 = 0
-1 - -2 = 1

If you squared it you would get -1, which is defined
sqrt-1 • sqrt-1 = -1

and if you cubed it, you would get a negative under a square root again, therefor it would be undefined.
sqrt-1 • sqrt-1 • sqrt-1 = -1 • sqrt-1 = -1(sqrt-1)

Sorry if this answer is confusing, I don’t have a scientific keyboard, I’ll get one soon.
8 0
2 years ago
Suppose sin(A) = 1/4. use the trig identity sin^2(A)+cos^2(A)=1 to find cos(A) in quadrant II. around to ten-thousandth.
larisa86 [58]

In quadrant II, \cos(A) will be negative. So

\sin^2(A) + \cos^2(A) = 1 \implies \cos(A) = -\sqrt{1 - \sin^2(A)} = -\dfrac{\sqrt{15}}4 \approx \boxed{-0.9682}

8 0
1 year ago
Plz help im bad and i need to know the answer and free brainest
Amiraneli [1.4K]
There’s no picture?sorry can you repost?
3 0
2 years ago
For each right triangle below, find the missing side (Pythagorean’s Theorem) and the missing angle (Angle Sum theorem.)
valkas [14]

Answer:

a=21.2

n=√29

Step-by-step explanation:

90+68.2+a=180

a+158.2=180

a=21.2

2^2+5^2=n^2

4+25=n^2

n^2=29

n=\sqrt{29}

3 0
2 years ago
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