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3 years ago

9/16+5/12= help asap

Mathematics

2 answers:

navik [9.2K]3 years ago

8 0

$\frac{9}{16} + \frac{5}{12} = \frac{27}{48} + \frac{20}{48} = \frac{47}{48}$

galben [10]3 years ago

7 0

Answer: 47/48

Step-by-step explanation:

(9 × 12) + (5 × 16)

16 × 12

188

192

188 ÷ 4

192 ÷ 4

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The larger of two numbers is five more than the smaller number. If the sum of the numbers is 59, find the numbers

Andrews [41]

Answer:

27 and 32.

Step-by-step explanation:

Let the two numbers be A and B.

The larger number (let's use B) is 5 more than the smaller one (A). In other words:

$B=5+A$

Their sum is 59. So:

$A+B=59$

This is a system of equations. Solve by substituting the first equation into the second. Thus:

$A+(5+A)=59$

Combine like terms:

$2A+5=59$

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3 years ago

Solve (x + 5)2 = 48.

natita [175]

Answer:

x = -5 ±4sqrt(3)

Step-by-step explanation:

(x + 5)^2 = 48

Take the square root of each side

sqrt((x + 5)^2) = ±sqrt(48)

x+5 = ±sqrt(16*3)

x+5 = ±4sqrt(3)

Subtract 5 from each side

x = -5 ±4sqrt(3)

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3 years ago

A photograph measuring 3 inches by 2.5 inches is to be enlarged so that the smaller side, when enlarged, will be 8 inches. How l

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3 years ago

Two athletic teams play a series of games; the first team to win 4 games is declared the overall winner. Suppose that one of the

kodGreya [7K]

Answer:

p=0.7103 (4-game series)
p=0.6480 (2-game series)

Step-by-step explanation:

Let X be the random variable equal the the first 4 straight wins. An overall win for the stronger team implies a negative binomial function with the parameters n=4, p=0.6:

$P(X=4)={{i-1}\choose {4-1}}0.6^40.4^{i-4},\ i=4,5,6,7$

#We find probabilities for the different values of i:

$P(X=4)={3\choose 3}0.6^4=0.1296\\\\P(X=5)={4\choose 3}0.6^40.4^1=0.2074\\\\P(X=6)={5\choose 3}0.6^40.4^2=0.2074\\\\P(X=4)={6\choose 3}0.6^40.4^3=0.1659$

Hence, probability of the stronger team winning overall is:

$=P(X=4)+P(X=5)+P(X=6)+P(X=7)\\\\=0.7103$

#Define Y as the random variable for winning 2/3 games.:

$P(Y=2)={1\choose 1}0.6^2=0.3600\\\\P(Y=3)={2\choose3}0.6^20.4=0.2880\\\\P(win)=0.2880+0.3600=0.6480$

Hence, probability of the stronger team winning in 2 out 3 game series is 0.6480

The stronger team has a higher chance of winning in a 4-game series(0.7103>0.6480)

8 0

3 years ago