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WINSTONCH [101]
3 years ago
10

The absolute value of a positive integer is a negative integer​

Mathematics
1 answer:
nikdorinn [45]3 years ago
7 0

Answer:

that is incorrect

Step-by-step explanation:

absolute value cannot be negative, it is always a positive.

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Jane corporation produces model toy cars each sells for $29 99 sense its variable cost per unit is $14 25 sense what is the brea
n200080 [17]

Answer:

Break-even point in units= 20,000

Step-by-step explanation:

Giving the following information:

Selling price per unit= $29.99

Unitary variable cost= $14.25

Fixed costs= $314,800

<u>To calculate the break-even point in units, we need to use the following formula:</u>

Break-even point in units= fixed costs/ contribution margin per unit

Break-even point in units= 314,800 / (29.99 - 14.25)

Break-even point in units= 20,000

5 0
3 years ago
EASY 7TH GRADE MATH 6 out of 8 dentists recommend crest toothpaste. In a group of 156 dentists, how many of them recommend crest
Novay_Z [31]

Answer:

117

Step-by-step explanation:

6/8 = ?/156

156/8 = 19.5

19.5 x 6 = 117

6/8 = 117/156

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2 years ago
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Analyze the graph of the exponential decay function the intial value is
Kipish [7]

Answer:

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Step-by-step explanation:

4 0
3 years ago
Need help please, does any one know how to do this​
ziro4ka [17]

Answer:

  • (6-u)/(2+u)
  • 8/(u+2) -1
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Step-by-step explanation:

There are a few ways you can write the equivalent of this.

1) Distribute the minus sign. The starting numerator is -(u-6). After you distribute the minus sign, you get -u+6. You can leave it like that, so that your equivalent form is ...

  (-u+6)/(u+2)

Or, you can rearrange the terms so the leading coefficient is positive:

  (6 -u)/(u +2)

__

2) You can perform the division and express the result as a quotient and a remainder. Once again, you can choose to make the leading coefficient positive or not.

  -(u -6)/(u +2) = (-(u +2)-8)/(u +2) = -(u+2)/(u+2) +8/(u+2) = -1 + 8/(u+2)

or

  8/(u+2) -1

Of course, anywhere along the chain of equal signs the expressions are equivalent.

__

3) You can separate the numerator terms, expressing each over the denominator:

(-u +6)/(u+2) = -u/(u+2) +6/(u+2)

__

4) You can also multiply numerator and denominator by some constant, say 3:

  -(3u -18)/(3u +6)

You could do the same thing with a variable, as long as you restrict the variable to be non-zero. Or, you could use a non-zero expression, such as 1+x^2:

  (1+x^2)(6 -u)/((1+x^2)(u+2))

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3 years ago
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