
All terms have an x in them, so you factor that out first to get

Now the 2nd degree equation will be of the form (3x- ... y)(x- ... y) and by just trying you find that the ... is just 1. So the factorization is:

Umm, I think it is the first one.
Since the factors are (x+5)(x^2-4x+6)
the zeros would be 2+i√2 and 2−i√2
For the triangle the value for w would be 11. Im not 100% sure for the other ones though. Sorry
The function given is a line with one zero at the center (0,0)