I don't think those two expressions would even be equal unless w = 0. You can't just add in a 2 from nowhere.
The midpoints are (8,3) and (6.5,6).
<u>Step-by-step explanation</u>:
Midpoint formula = ((x1+x2)/2 , (y1+y2)/2)
(x1,y1) = (5,2)
(x2,y2) = (11,4)
Midpoint = ((5+11)/2 , (2+4)/2)
⇒ ((16/2) , (6/2))
⇒ (8,3)
(x1,y1) = (3,8)
(x2,y2) = (10,4)
Midpoint = ((3+10)/2 , (8+4)/2)
⇒ ((13/2) , (12/2))
⇒ (6.5,6)
Answer:

Step-by-step explanation:
Given


Required
The length of the diagonals
First, calculate the length of AB using:

So, we have:




The diagonal of a square is calculated using:

Where x is the length of each side.
So:


-- approximated
We have,
(2y)^3 × y^-1
Simplify the term (2y)^3
= 8y^3 × y^-1
Now, multiply the terms with the same base y by adding their exponents.
Note: Using exponent product rule x^y × x^z = x^(y+z)
= 8y^{3+(-1)}
= 8y^(3-1)
= 8y^(3-1)
= 8y^2