Answer:
we know that
the relationship between the 2-dimensional polar and Cartesian coordinates is
r = √(x² + y²)
Θ = tan⁻¹ (y/x)
so
Part a) (2, −2)---------> this point belong to the IV quadrant
r = √(x² + y²)------ r = √(2² + (-2)²)-----> r=√8
Θ = tan⁻¹ (y/x)---- Θ = tan⁻¹ (2/2)----> 45°
remember that the point belong to the IV quadrant
so
Θ=360-45-----> Θ=315°
the answer part A) is
(r,Θ)=(√8,315°)
Part b) (-1, 3)---------> this point belong to the II quadrant
r = √(x² + y²)------ r = √(-1² + (3)²)-----> r=√10
Θ = tan⁻¹ (y/x)---- Θ = tan⁻¹ (3/1)----> 71.57°
remember that the point belong to the II quadrant
so
Θ=180-71.57-----> Θ=108.43°
the answer part B) is
(r,Θ)=(√10,108.43°)
mark me branlest plz hope it helps
She has a 1 in 5 chance of getting the green ball because there is one of each color marble
For this case, what you should know is that a linear function has a constant average rate of change, because its slope is constant.
Table number two from left to right represents a linear function.
The line is:
y-yo = m (x-xo)
Where
The slope is:
m = (0 - (- 5)) / (2-1)
m = 5/1
m = 5
The line is:
y-0 = 5 (x-2)
Rewriting:
y = 5x-10
Answer:
Table two from left to right.
The equation is:
y = 5x-10
The number 12 has more factors
(-2,5) (2,0)
Just use the slope formula to find slope.
m = (y2-y1)/(x2-x1)
m = (0-5)/(2+2)
m = -5/4
Hence, the slope of the line is -5/4.
