Answer:
75 miles
Step-by-step explanation:
Let r represent the region bound by the graphs of y=sin(π x) and y=x³-4x.
Perpendicular lines have gradients that multiply to give -1
So, the gradient of the line we need is -1/0.2 = -5
If we have the gradient and a point in the line, we can work out the equation using the formula:
y - y1 = m(x - x1)
where m = gradient, y1 = y-coordinate and x1 = x-coordinate of the same point
So, we substitute in our values, and we get:
y - -8 = -5(x - -7)
y+8 = -5x-35
y = -5x-43
Hope I helped! xx
Answer:
φ ≈ 1.19029 radians (≈ 68.2°)
Step-by-step explanation:
There are simple formulas for A and φ in this conversion, but it can be instructive to see how they are derived.
We want to compare ...
y(t) = Asin(ωt +φ)
to
y(t) = Psin(ωt) +Qcos(ωt)
Using trig identities to expand the first equation, we have ...
y(t) = Asin(ωt)cos(φ) +Acos(ωt)sin(φ)
Matching coefficients with the second equation, we have ...
P = Acos(φ)
Q = Asin(φ)
The ratio of these eliminates A and gives a relation for φ:
Q/P = sin(φ)/cos(φ)
Q/P = tan(φ)
φ = arctan(Q/P) . . . . taking quadrant into account
__
We can also use our equations for P and Q to find A:
P² +Q² = (Acos(φ))² +(Asin(φ))² = A²(cos(φ)² +sin(φ)²) = A²
A = √(P² +Q²)
_____
Here, we want φ.
φ = arctan(Q/P) = arctan(5/2)
φ ≈ 1.19029 . . . radians
<span>The function can be represented as
y = f(x) =px(q -x)
So from the coordinate (6, 0)
y = 0 and x = 6
Substituting into the equation we have
0 = 6p(q - 6)
0 = 6pq -36p
6pq = 36p
q = 36p/ 6p
q = 6</span>
