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mestny [16]
3 years ago
10

A rectangular skateboard park has an area of x^2+15x+56 what are the possible dimensions

Mathematics
1 answer:
alexira [117]3 years ago
7 0
For this case we have the following expression:
 x ^ 2 + 15x + 56
 We can factor this expression to find the possible dimensions of the rectangle.
 Factoring we have:
 (x + 7) (x + 8)
 Answer:
 
the possible dimensions are:
 
(x + 7) * (x + 8)
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A line segment has endpoints A(4, 8) and B(2, 10). The point M is the midpoint of AB. What is an equation of a line perpendicula
Vera_Pavlovna [14]
I)

The Midpoint M of the line segment AB is found using the Midpoint formula:

M=( \frac{4+2}{2} , \frac{8+10}{2})=(3, 9)

ii)

the slope of the line through A and B is found by the slope formula:

m= \frac{y_1-y_2}{x_2-x_1}= \frac{10-8}{2-4}= \frac{2}{-2}=-1

iii)

the product of the slopes of 2 perpendicular lines is -1, so the slope of the line perpendicular to the line through A and B is -1/(-1)=1

iv) 

the equation of the line with slope 1, which contains point M(3, 9) is found by the slope point form equation of a line:

y-9=1(x-3)

y-9=x-3

y=x+6


Answer: y=x+6

7 0
3 years ago
8s+4(4s-3)=4(6s+4)-4​
elena55 [62]

Answer:

There is no solution.

5 0
3 years ago
The bar graph below shows the student's favorite ice cream flavors. a) Use the graph's lines as a ruler to draw the intervals on
PtichkaEL [24]
Butter pecan: 25
Vanilla: 35
Chocolate: 50

The dotted line between 20 and 30 (butter pecan) will be nothing more than anything including 5. In this case, it is 25 counting up to 30.
The solid lines directly leading to a number will be that number, for instance, chocolate is 50.
3 0
2 years ago
77. the volume of a cube is increasing at a rate of <img src="https://tex.z-dn.net/?f=10%20%5Cmathrm%7B~cm%7D%5E%7B3%7D%20%2F%20
Colt1911 [192]

Answer:

\displaystyle \frac{4}{3}\text{cm}^2/\text{min}

Step-by-step explanation:

<u>Given</u>

<u />\displaystyle \frac{dV}{dt}=10\:\text{cm}^3/\text{min}\\ \\V=s^3\\\\SA=6s^2\\\\\frac{d(SA)}{dt}=?}\:;s=30\text{cm}

<u>Solution</u>

(1) Find the rate of the cube's edge length with respect to time at s=30:

\displaystyle V=s^3\\\\\frac{dV}{dt}=3s^2\frac{ds}{dt}\\ \\10=3(30)^2\frac{ds}{dt}\\ \\10=3(900)\frac{ds}{dt}\\\\10=2700\frac{ds}{dt}\\\\\frac{10}{2700}=\frac{ds}{dt}\\\\\frac{ds}{dt}=\frac{1}{270}\text{cm}/\text{min}

(2) Find the rate of the cube's surface area with respect to time at s=30:

\displaystyle SA=6s^2\\\\\frac{d(SA)}{dt}=12s\frac{ds}{dt}\\ \\\frac{d(SA)}{dt}=12(30)\biggr(\frac{1}{270}\biggr)\\\\\frac{d(SA)}{dt}=\frac{360}{270}\biggr\\\\\frac{d(SA)}{dt}=\frac{4}{3}\text{cm}^2/\text{min}

Therefore, the surface area increases when the length of an edge is 30 cm at a rate of \displaystyle \frac{4}{3}\text{cm}^2/\text{min}.

6 0
2 years ago
What is a solution to the equation 6t=124?
Vladimir79 [104]
The solution to this question is 20.6666666
7 0
2 years ago
Read 2 more answers
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