The expression factorized completely is (h +2k)[(h+2k) + (2k-h)]
From the question,
We are to factorize the expression (h+2k)²+4k²-h² completely
The expression can be factorized as shown below
(h+2k)²+4k²-h² becomes
(h+2k)² + 2²k²-h²
(h+2k)² + (2k)²-h²
Using difference of two squares
The expression (2k)²-h² = (2k+h)(2k-h)
Then,
(h+2k)² + (2k)²-h² becomes
(h+2k)² + (2k +h)(2k-h)
This can be written as
(h+2k)² + (h +2k)(2k-h)
Now,
Factorizing, we get
(h +2k)[(h+2k) + (2k-h)]
Hence, the expression factorized completely is (h +2k)[(h+2k) + (2k-h)]
Learn more here:brainly.com/question/12486387
Answer:
a) 3x-5=16
b) 30cm
Step-by-step explanation:
a) 5(x-1)=2(x+8)
5x-5=2x+16
5x-2x-5=16
3x-5=16
b) solving the equation gives x=7
put x=7 into first line, 5(7-1)=30cm
to check we can place it into second one as well
2(7+8)=30cm
Answer:
x>8
Step-by-step explanation:
4+3x>24
-4 -4
3x > 24
/3 /3
x > 8
Per means divide. So..
Step 1. Find ur equation. 63\3
Step 2. Solve ur equation. 63\3 = 21
I think thats right.
