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3 years ago

Helpppp No links plz

Mathematics

1 answer:

Jet001 [13]3 years ago

6 0

Answer:

the third one ig

Step-by-step explanation:

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PLZ HURRY!!!!!!!!!!!!!<br> Simplify. <br> −4x^2(5x^4−3x^2+x−2)

Simora [160]

$\bold{Answer}$

$\boxed{\bold{-20x^6+12x^4-4x^3+8x^2}}$

$\bold{Explanation}$

$\bold{Simplify: \ -4x^2\left(5x^4-3x^2+x-2\right)}$

$\bold{------------------}$

$\bold{Distribute \ Parenthesis}$

$\bold{\left(-4x^2\right)\cdot \:5x^4+\left(-4x^2\right)\left(-3x^2\right)+\left(-4x^2\right)x+\left(-4x^2\right)\left(-2\right)}$

$\bold{Apply \ Addition \ / \ Subtraction \ Rules: \ +\left(-a\right)=-a,\:\:\left(-a\right)\left(-b\right)=ab}$

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$\bold{Simplify \ -4\cdot \:5x^4x^2+4\cdot \:3x^2x^2-4x^2x+4\cdot \:2x^2: \ -20x^6+12x^4-4x^3+8x^2}$

$\bold{-20x^6+12x^4-4x^3+8x^2}$

$\boxed{\bold{Eclipsed}}$

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3 years ago

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GalinKa [24]

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Step-by-step explanation:

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3 years ago

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Alla [95]

Answer:

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Step-by-step explanation:

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3 years ago

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shusha [124]

$\text{Hi there! :)}$

$\large\boxed{f'(2) = -\frac{16}{27} }$

$f'(x) = \frac{(5 + x^{2} )(-2x) - (7 - x^{2} )(2x)}{(5+x^{2})^{2} } \\\\f'(x) = \frac{-10x-2x^{3}- 14x + 2x^{3} }{(5+x^{2})^{2} } \\\\f'(x) = \frac{-24x}{(5+x^{2})^{2} }\\\\ \text{Solve for the derivative at f'(2) using substitution:}\\\\f'(2) = \frac{-24(2)}{(5+2^{2})^{2} } \\\\f'(2) = \frac{-48}{81} \\\\\text{Simplify:}\\\\f'(2) = -\frac{16}{27}$