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3 years ago

HELP I WILL MARK BRAINLIEST

Mathematics

1 answer:

Blababa [14]3 years ago

8 0

Answer:

#5 - C

#7 - A

Step-by-step explanation:

If two items are similar, it means that the angles and figure itself have not changed, just the size. The two objects are prototional to each other.

In order to find the length of one side, we have to find what the size difference is, if that makes sense. We have to figure out the number that the smaller size is multiplied by in order to get the bigger number (or the other way around).

#5:

Side LK and side DE are preportional. We can divide 35 by 10 to figure out the proportion size. 35/10=3.5. Then we can take that and use it to find the other side. MK and FD are proportional. We can now take 22 and multiply it by 3.5 to get the new side length. 22x3.5=77

#7:

Same thing. 12/8=1.5, which is the proportional size change. We can now take the already exisiting number and multiply it. 5x1.5=7.5

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David and Lacey are 2000 feet apart on a coastline. They each look at the same boat in the water. The angle between the coastlin

Ulleksa [173]

By using the given distances and directions, we have;

Part A: 1083.5 feet

Part B: 1921.37 feet

Part C: 58.05°

<h3>How can the distances and directions be calculated?</h3>

The distance between David and Lacey = 2000 feet

David's angle to the boat = 70°

Lacey's angle to the boat = 32°

Part A

The distance of the boat from David is found as follows;

Imaginary lines drawn from the boat to David and then to Lacey form a triangle.

In the triangle, let A = 70°

B = 32°

Therefore by the sum of angles in a triangle, we have;

C = 180° - (70° + 32°) = 78°

By using sine rule we have;

$\frac{a}{sin(A)} = \frac{b}{sin( B )} = \frac{c}{sin(C)}$

David's distance from the boat, b, is therefore;

$\frac{b}{sin( 32 )} = \frac{2000}{sin(78)}$

The angle subtended by the coastline, C, is therefore;

$b = \frac{2000}{sin(78)} \times sin( 32 ) = 1083.5$

David's distance from the boat is 1083.5 feet

Part B

The distance between the boat and Lacey is found as follows;

$\mathbf{ \frac{a}{sin( 70)} }= \frac{2000}{sin(78)}$

$a = \frac{2000}{sin(78)} \times sin( 70 ) = 1921.37$

Lacey's distance from the boat is 1921.37 feet

Part C

When b = 1200 feet, we have;

Finding the vertical distance of the boat from the coastline, we have;

1083.5 × sin(70) = 1018.17

We have;

$\frac{1200}{sin(90)} = \frac{1018.17}{sin( B' )}$

${sin( B' )} = \frac{sin(90)}{1200} \times 1018.17$

The angle between the coastline and his view to the boat, B', is therefore;

B' = arcsine (1018.17÷1200) = 58.05°

Learn more about sine rule here:

brainly.com/question/4372174

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