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Ad libitum [116K]
3 years ago
9

Write your answer with no space and any fraction with “/“

Mathematics
1 answer:
nirvana33 [79]3 years ago
4 0

Answer:

y+3=2(x-1)

Step-by-step explanation:

Point-slope form is y-y_1 = m (x-x_1). In order to write a linear equation using this form, the y_1, x_1 and m must be substituted by real numbers.

The m represents the slope of the equation. We know that the answer has to be parallel to the line y=2x-1. y=2x-1 is already in slope-intercept form, or y=mx+b, in which m represents the slope. We can see that the 2 is in place of that m, therefore 2 is the slope of y=2x-1. Lines that are parallel have the same slope, so we know that the slope of the new equation must be 2 as well.

The x_1 and y_1 represent the x and y values of one point that the line passes through. We know that the new equation must pass through the point (1, -3), so we'll substitute 1 in place of the x_1 and -3 in place of the y_1.

Substituting for those three values will give you an equation like this, therefore it is the answer:

y-(-3)= 2(x-(1))

y+3= 2(x-1)

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Given that x=3sin​​θ-2 and y=3cos​​​θ+4.Show that (x+2)²+ (y-4)²=9​​​​​​
asambeis [7]

Answer:

First, plug-in x and y as 3sin​​θ-2 and 3cos​​​θ+4 into the equation, respectively:

((3\sin (\theta)-2)+2)^2 + ((3\cos (\theta)+4)-4)^2 = 9

Then, +2 and -2 cancel out and +4 and -4 cancel out as well, leaving you with:

(3\sin(\theta))^2+(3\cos(\theta))^2=9

We can factor out 3^2 = 9 from both equations:

9(\sin(\theta)^2+cos(\theta)^2) = 9

We know from a trigonometric identity that \sin(\theta)^2+cos(\theta)^2 = 1, meaning we can reduce the equation to:

9(1) = 9

9=9

And therefore, we have shown that (x+2)^2 + (y-4)^2 = 9, if x=3sin​​θ-2 and y=3cos​​​θ+4.

Hope this helped you.

7 0
3 years ago
Pls help me this is due tomorrow
pishuonlain [190]

i dont know

Step-by-step explanation:

3 0
2 years ago
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(a + b)(a – b) = a2 + b2 true or false?
Alja [10]
False it's a2-b2 :))))
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Write the equation in standard form for the circle that has a diameter with endpoints (22,0) and (2,0)
vovikov84 [41]

Answer:

(x - 12)² + y² = 100

Step-by-step explanation:

The standard form of the equation of a circle is;

(x - a)² + (y - b)² = r²

where:

a and b are the coordinates of the centre of the circle

r is the radius

We are given the coordinates of the endpoints of the diameter as; (22,0) and (2,0)

Thus, the centre of the circle would be at the mid point of the endpoints of the diameter.

Coordinates of the centre is;

((22 + 2)/2), (0 +0)/2))

This is;

(12, 0)

So, a = 12 and b = 0

Now,to get the radius r, we will use the formula;

r = √[(x2 - x1)² + (y2 - y1)²]

Where;

(x1, y1) and (x2, y2) are 2 points namely (12,0) and (22, 0)

r = √[(12 - 22)² + (0 - 0)²]

r = √(-10)²

r = √100

r = 10

Thus,equation of the circle is;

(x - 12)² + (y - 0)² = 10²

(x - 12)² + y² = 100

7 0
3 years ago
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