The value of 7 in 26..74 is 0.7
The value of 7 in 37.596 is 7.
1/10 the value of 7 in 26.74 is 0.07 and 0.07 ≠ 7.
So, statement a) is incorrect.
1/100 the value of 7 in 26.74 is 0.007 and 0.007 ≠ 7.
So, statement c) is incorrect.
100 times the value of 7 in 26.74 is 70 and 70 ≠ 7.
So, statement d) is incorrect.
10 times the value of 7 in 26.74 is 7 and 7 = 7.
So, statement b) is correct and it correctly compares two values.
Upper Tolerance
Remark
The 11/16 is the only thing that will be affected. The three won't go up or down when we add 1/64 so we should just work with the 11/16. We need only add 11/16 and 1/64 together to see what the upper range is. Later on we can add 3 into the mix.
Solution
<u>Upper Limit</u>
Now change the 11/16 into 64. Multiply numerator and denominator or 11/16 by 4
Which results in
With a final result for the fractions of 45/64
So the upper tolerance = 3 45/64
<u>Lower Tolerance</u>
Just follow the same steps as you did for the upper tolerance except you subtract 1/64 like this.
Your answer should be 3 and 43/64
Answer:
True
Step-by-step explanation:
Type I and Type II are not independent of each other - as one increases, the other decreases.
However, increases in N cause both to decrease, since sampling error is reduced.
A small sample size might lead to frequent Type II errors, i.e. it could be that your (alternative) hypotheses are right, but because your sample is so small, you fail to reject the null even though you should.
Answer:
-1 & -2
Step-by-step explanation:
x²+3x+2
x²+2x+x+2
(x²+2x)+(x+2)
x(x+2)+1(x+2)
(x+1)(x+2)
