78% = 78 / 100 = 0.78
What is 78% of 380
= 78% * 380
= 0.78 * 380
= 296.4
U said I should round it up IF NECESSARY so yeah....
Answer: itz d plz trust me
Answer:
Step-by-step explanation:
f(x) = (x - 1)/(x - 3) < 0
The critical points are x = 1 and x = 3
When x < 1, f(x) > 0
When 1 < x < 3, f(x) < 0
When x > 3, f(x) > 0
Note when x = 3 f(x) has no value and when x = 1 f(x) = 0.
I can't see all the graphs very well but there should be a red line between 1 and 3 with a clear circle on x = 1 and x = 3.
Looks like its the last choice.
Try this:
1) note that weight of pure antifreeze before mixing and after mixing is the same. So, if 'x' is weight of pure antifreeze in 50% solution, it is possible to make up equation before mixing: 0.5x+0.2*90.
2) there are 0.2*90=18 gal. of pure antifreeze in the 20% solution. If 'x' gal. is the weight of pure antifreeze in 50% sol. and 18 gal. is the weight of pure antifreeze in 20% sol., it is possible to make up an equation after mixing: 0.4(x+18).
3) using the both parts: 0.5x+0.2*90=0.4(x+18) ⇒ x=54 gal. of <u>pure</u> weight.
4) to find 50% solution of 54 gal. pure weight just 54:0.5=108 gal.
Answer: 108 gal.
