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3 years ago

How do I write the rule for the nth term of the sequence -4, 8, -12, 16?

Mathematics

1 answer:

SVETLANKA909090 [29]3 years ago

6 0

Answer:

Step-by-step explanation:

The result of adding a number plus the next number will be alternating 4,-4,4,-4,4,-4......

-4+8 = 4

8+ -12= -4

-12 +16 =4

16+-20=-4

-20 + 24=4

24+-28 = -4

So you need to calculate what number plus the previous number has as result 4 or -4 alternating

8 + ? = -4

?= -4 -8

?=-12

-12+? =4 ?=12+4 ?=16

16+? =-4 / = -16-4 ?=-20

ANOTHER METHOD

4*-1=-4

4*2=8

4*-3=-12

4*4 = 16

4*-5=-20

4*6=24

4*-7=-28

4*8=32

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a herd of 86 horses has 75 white and some black horses.what is the ratio of black horses to white horses?

Naddik [55]

Answer:11 black horses : 75 white horses

Step-by-step explanation:

we know thw white horses and how many there are but we dont know how many black ones so u take the number of white horses and subtart it from the total and get the number of black horses

8 0

3 years ago

Read 2 more answers

What is ∛1728. Then multiplied by ∛14903

NeTakaya

Cube root of 1728 is 12 and on multiplying it by cube root of 14903 we get 295.306.

<u>Solution: </u>

Need to calculate $\sqrt[3]{1728}$ and then multiply the result by $\sqrt[3]{14903}$

Let us first evaluate $\sqrt[3]{1728}$

$\Rightarrow \sqrt[3]{1728}=\sqrt[3]{12 \times 12 \times 12}=12$

As need to multiply 12 by $\sqrt[3]{14903}$

$\Rightarrow 12 \times \sqrt[3]{14903}$

On solving $\sqrt[3]{14903}$ , we get

$\sqrt[3]{14903}=24.608$

$\Rightarrow 12 \times \sqrt[3]{14903}=12 \times 24.608=295.306$

Hence cube root of 1728 is 12 and on multiplying it by cube root of 14903 we get 295.306.

8 0

2 years ago

Today there are a total of six toll-free area codes: 800, 844, 855, 866, 877, and 888. Assume that all seven digits for the rest

Ludmilka [50]

Answer:

$6 \times 10^{7}$

Step-by-step explanation:

Total number of toll-free area codes = 6

A complete number will be of the form:

800-abc-defg

Where abcdefg can be any 7 numbers from 0 to 9. This holds true for all the 6 area codes.

Finding the possible toll free numbers for one area code and multiplying that by 6 will give use the total number of toll free numbers for all 6 area codes.

Considering: 800-abc-defg

The first number "a" can take any digit from 0 to 9. So there are 10 possibilities for this place. Similarly, the second number can take any digit from 0 to 9, so there are 10 possibilities for this place as well and same goes for all the 7 numbers.

Since, there are 10 possibilities for each of the 7 places, according to the fundamental principle of counting, the total possible toll free numbers for one area code would be:

Possible toll free numbers for 1 area code = 10 x 10 x 10 x 10 x 10 x 10 x 10 = $10^{7}$