How do I write the rule for the nth term of the sequence -4, 8, -12, 16?
1 answer:
Answer:
Step-by-step explanation:
The result of adding a number plus the next number will be alternating 4,-4,4,-4,4,-4......
-4+8 = 4
8+ -12= -4
-12 +16 =4
16+-20=-4
-20 + 24=4
24+-28 = -4
So you need to calculate what number plus the previous number has as result 4 or -4 alternating
8 + ? = -4
?= -4 -8
?=-12
-12+? =4 ?=12+4 ?=16
16+? =-4 / = -16-4 ?=-20
ANOTHER METHOD
4*-1=-4
4*2=8
4*-3=-12
4*4 = 16
4*-5=-20
4*6=24
4*-7=-28
4*8=32
You might be interested in
You work backwards so you first do
2,340 ÷ 26 = 90
You then proceed to do
90 ÷ 15 = 6
So your final answer is 6
Answer:
C'est question pas difficile
Answer:
If n is three,
-2n(5+n-8-3n)
-2*3 (5+3-8-3*3)
-6(0-9)
-6*-9
54
Answer:
2
Step-by-step explanation:
i think give me brain pleaz
Answer:
Only x=-2 is an extraneous solution is the answer
Step-by-step explanation: