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3 years ago

What is the volume? 2 mm 2 mm 2 mm

Mathematics

2 answers:

never [62]3 years ago

6 0

Answer:

Its depends on the shape of the container. If its a cube then it is 8mm

Step-by-step explanation:

to find volume, its length x width x height so

2mm x 2mm x 2mm = 8mm

vivado [14]3 years ago

5 0

Answer:

8mm

Step-by-step explanation:

A cube with 2mm is 8mm

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1²+3²+4²+.......+(2n-2)²= ⅓n(2n-1)(2n+1)

sergiy2304 [10]

1² + 3² + 4² + 4(n - 1)² = ¹/₃n(2n - 1)(2n + 1)
1² + 3² + 4² + (2n - 2)² = ¹/₃n(2n - 1)(2n + 1)
  1 + 9 + 16 + (2n - 2)(2n - 2) = ¹/₃n(2n(2n + 1) - 1(2n + 1))
10 + 16 + (2n(2n - 2) - 2(2n - 2)) = ¹/₃n(2n(2n) + 2n(1) - 1(2n) - 1(1) 16 + (2n(2n) - 2n(2) - 2(2n) + 2(2)) = ¹/₃n(4n² + 2n - 2n - 1)
26 + (4n² - 4n - 4n + 4) = ¹/₃n(4n² - 1)
26 + (4n² - 8n + 4) = ¹/₃n(4n² - 1)
  26 + 4n² - 8n + 4 = ¹/₃n(4n²) - ¹/₃n(1)
  4n² - 8n + 4 + 26 = 1¹/₃n³ - ¹/₃n
  4n² - 8n + 30 = 1¹/₃n³ - ¹/₃n
  + ¹/₃n + ¹/₃n
   4n² - 7²/₃n + 30 = 1¹/₃n³
-1¹/₃n³ + 4n² - 7²/₃n + 30 = 0
-3(-1¹/₃n³ + 4n² - 7²/₃n + 30) = -3(0)
-3(-1¹/₃n³) - 3(4n²) - 3(-7²/₃n) - 3(30) = 0
  4n³ - 12n² + 23n - 90 = 0

8 0

4 years ago

F(x)=2/3x+4 then what is the translation of h(x)= —f(x)

choli [55]

I would think a reflection across the x-axis but I’m not sure

7 0

3 years ago

-12x + (-4x) + (-5x) =

Radda [10]

Answer:

=-21x

Step-by-step explanation:

-12-4 =-16

-16-5=-21

5 0

3 years ago

Read 2 more answers

The U.S. Energy Information Administration (US EIA) reported that the average price for a gallon of regular gasoline is . The US

alexandr1967 [171]

Answer:

The answer is "23, 62, and 139"

Step-by-step explanation:

In point a:

$\to \sigma = \$0.24\\\\ \to E = \$0.10\\\\ 95\% \text{confidence level of the z}: \\\\\to \alpha = 1 - 95\% = 1 - 0.95 = 0.05\\\\\to \frac{\alpha}{2} = \frac{0.05}{2} = 0.025\\\\\to Z_{\frac{\alpha}{2}} = Z_{0.025} = 1.96\\\\$

Calculating the sample size:

$\to n = (\frac{(Z_{\frac{\alpha}{2}} \times \sigma)}{E})^2$

$= (\frac{(1.96 \times 0.24 )}{0.10})^2\\\\= 22.13 \approx 23$

In point b:

$\to \sigma = \$0.24\\\\\to E = \$0.06\\\\\to Z_{\frac{\alpha}{2}} = Z_{0.025} = 1.96\\\\\to n = (\frac{(Z_{\frac{\alpha}{2}} \times \sigma )}{E})^2\\\\$

$= (\frac{(1.96 \times 0.24 )}{0.06})^2\\\\= 61.47 \approx 62$

In point c:

$\to \sigma = \$0.24\\\\\to E =\$0.04\\\\\to Z_{\frac{\alpha}{2}} = Z_{0.025} = 1.96\\\\\to n = (\frac{(Z_{\frac{\alpha}{2}} \times \sigma )}{E})^2\\\\$

$= (\frac{(1.96\times 0.24 )}{0.04})^2 \\\\=138.30 \approx 139$

4 0

3 years ago

HELP MEEEE!!!!!!!!!!!!!!!!!!!! I will give brainliest to whoever answers first.

aleksklad [387]

Answer:

B = 114

Step-by-step explanation:

and i answered first

3 0

3 years ago