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sashaice [31]
3 years ago
10

-9(10x+4)-11=7(x-2)+452

Mathematics
2 answers:
timama [110]3 years ago
5 0

Answer:

Step-by-step explanation:

X=-5

Hope this helps mark me as brainiest

Svetach [21]3 years ago
3 0

Answer:x=-5

Step-by-step explanation:

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How do I solve what is 3 and 3 fifths minus two thirds
stealth61 [152]
3 3/5 - 2/3

1-you convert 3 3/5 to an improper fraction (18/5)

2-then you find a common denominator between then (15)

3-then subtract

your answer would be 49/15
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Fund the value of x! I need this asap!! Please dont get it wrong and first correct answer gets brainliest!!
grin007 [14]

Answer:

Step-by-step explanation:

What is the equation???

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Carla can swim 3/4 of a lap in 1/30 of an hour. How many laps can she swim in 1 full hour? (laps per hour)​
ValentinkaMS [17]

Answer:

3/4 x 30 = 90/4

= 22.5 laps per hour

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
The number of people, N, that Denis can invite to his party is dependent on the amount of money, x, in dollars,
gulaghasi [49]

Answer:

N(h) = 2h + 6

Step-by-step explanation:

A model of the number of people that Denis can invite to his party:

N(x) = x/25.............(1)

Where x = amount of money saved

Amount of money saved can be modeled by the equation:

M(h) = 50h + 150...........(2)

In the above model, h = number of overtime hours

M(h) = amount of money saved = x

Therefore equation (1) can be re - written as:

N(x) = M(h)/25.................................(3)

Substituting equation (2) into equation (3)

N(h) = \frac{50h + 150}{25} \\N(h) = \frac{50h}{25} + \frac{150}{25} \\N(h) = 2h + 6

Find an explicit expression that models the number of people that Denis can invite to his party if he worked h  overtime hours this week can be expressed as:

N(h) = 2h + 6

7 0
4 years ago
Thorium -228 is a radioactive substance that decays 50% every 1.9 years. How much of a 50 gram sample will exist after 22.8 year
Evgesh-ka [11]

Answer:

A=0.0122\ gr

Step-by-step explanation:

The exponential decrease formula that we must use is:

A=A_0e^ {-kt}

Where A is the amount of thorium as a function of time

A_0 is the initial amount and k is the decrease rate

We know that initially there are 50 gr and that you decay 50% every 1.9 years.

So

A=A_0*0.5=50*0.5 = 25\\\\t=1.9

25=50e^ {-k(1.9)}

We solve the equation for k

0.5=e^ {-k(1.9)}

ln(0.5)=ln(e^ {-k(1.9)})

ln(0.5)=-k(1.9)

-1.9k=ln(0.5)

k=-\frac{ln(0.5)}{1.9}\\\\k=0.3648

After 22.8 years the amount of thorium that exists is:

A=50e^ {-0.3648(22.8)}

A=0.0122\ gr

5 0
4 years ago
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