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oksian1 [2.3K]
2 years ago
10

Please help I need work shown!!

Mathematics
2 answers:
likoan [24]2 years ago
7 0

3x-11=2x+11

x=22

3x-11=55

2x+11=55

55+55+2y=180

2y=70

y=35

x=22 , y=35

bekas [8.4K]2 years ago
3 0
Ok done. Thank to me :>

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Solve the system of linear equations below.
Reika [66]

Answer:

x = 1 , y = 3 thus: A is your Anser

Step-by-step explanation:

Solve the following system:

{2 x + y = 5 | (equation 1)

x + y = 4 | (equation 2)

Subtract 1/2 × (equation 1) from equation 2:

{2 x + y = 5 | (equation 1)

0 x+y/2 = 3/2 | (equation 2)

Multiply equation 2 by 2:

{2 x + y = 5 | (equation 1)

0 x+y = 3 | (equation 2)

Subtract equation 2 from equation 1:

{2 x+0 y = 2 | (equation 1)

0 x+y = 3 | (equation 2)

Divide equation 1 by 2:

{x+0 y = 1 | (equation 1)

0 x+y = 3 | (equation 2)

Collect results:

Answer:  {x = 1 , y = 3

8 0
3 years ago
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If a/b=5/3 then 3a = ____.
Tresset [83]
Answer: 15
a=5, b=3
3a= 3x5= 15
3 0
3 years ago
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A 2L punch recipe calls for orange and ginger ale in the ratio of 2:5
Nastasia [14]

Answer:

a) 4/7 L = 0.57 L

b) 25/7 L = 3.57 L

Step-by-step explanation:

The ratio of orange juice to ginger ale is 2:5.

Add 2 + 5 = 7.

The ratio of orange juice to ginger ale to total drink is 2:5:7.

a) The fraction of orange juice is 2/7 of the total drink.

To make 2 L, you will need 2/7 of 2 L to be orange juice.

2/7 * 2 L = 4/7 L = 0.57 L

b) The fraction of ginger ale is 5/7 of the total drink.

5/7 * 5 L = 25/7 L = 3.57 L

5 0
3 years ago
The equation a=640s gives the relationship between s square miles and acres. Pam owns 7.5 square miles of farmland. How many acr
zhenek [66]
640 acres / 1 mi^2 

<span>7.5 mi^2 (640 acres / 1 mi^2) </span>

<span>= 4,800 acres </span>
7 0
3 years ago
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To study the output of a machine that fills boxes with cereal, a quality control engineer weighed 150 boxes of Brand X cereal. T
scoundrel [369]

Answer:

\sigma = 0.07770

Step-by-step explanation:

Given

The above table

Required

The standard deviation

First, calculate the class mid-point. This is the average of the class interval.

The mid-point x is:

x_1 = \frac{1}{2}(15.3 + 15.6) =\frac{1}{2} * 30.9 = 15.45

x_2 = \frac{1}{2}(15.6 + 15.9) =\frac{1}{2} * 31.5 = 15.75

x_3 = \frac{1}{2}(15.9 + 16.2) =\frac{1}{2} * 32.1 = 16.05

x_4 = \frac{1}{2}(16.2 + 16.5) =\frac{1}{2} * 32.7 = 16.35

x_5 = \frac{1}{2}(16.5 + 16.8) =\frac{1}{2} * 33.3 = 16.65

So, we have:

\begin{array}{cccccc}x & {15.45} & {15.75} & {16.05} & {16.35} & {16.65} \ \\ f & {14} & {25} & {84} & {18} & {9} \ \end{array}

Calculate mean

\bar x = \frac{\sum fx}{\sum f}

\bar x = \frac{15.45 * 14 + 15.75 * 25 + 16.05 * 84 + 16.35 * 18 + 16.65 * 9}{14 + 25 + 84 + 18 + 9}

\bar x = \frac{2402.4}{150}

\bar x = 16.016

The standard deviation is:

\sigma = \sqrt{\frac{\sum(x_i - \bar x)^2}{\sum f}}

\sigma = \sqrt{\frac{(15.45 - 16.016)^2+ (15.75  - 16.016)^2+ (16.05  - 16.016)^2+ (16.35   - 16.016)^2+ (16.65  - 16.016)^2}{14 + 25 + 84 + 18 + 9}}

\sigma = \sqrt{\frac{0.90578}{150}}

\sigma = \sqrt{0.00603853333}

\sigma = 0.07770

4 0
3 years ago
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