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3 years ago

Help please Find the value of x. *

Mathematics

2 answers:

salantis [7]3 years ago

5 0

Answer:

Step-by-step explanation:

Anettt [7]3 years ago

4 0

Answer:

$x=\sqrt{10^{2}-y^{2}}$

Step-by-step explanation:

$x^{2} +y^{2} =10^{2} \\x^{2} =10^{2}-y^{2}\\x=\sqrt{10^{2}-y^{2}}$

You might be interested in

How to get from 90 to 100 using multiplication or division

Nutka1998 [239]

Answer:

multiply 10 and divide by 9

Step-by-step explanation:

you multiply 90 by 10 and get 900 then divide 900 by 9 and u get 100

5 0

4 years ago

mart [117]

Answer:

66 inches ;

95.44 ;

Step-by-step explanation:

Given that:

Normal distribution with;

Mean(m) = 66 inches

Standard deviation (s) = 3 inches

A.) If a horse is chosen at random, Expected height will be equal to the mean of the distribution = 66 inches

B.) percentage horses who are between 60 and 72 inches

Zscore = ( x - m) / s

x = 60

Zscore = (60 - 66) / 3

Zscore = - 6/3

= - 2

P(Z < - 2) = 0.0228

Zscore = ( x - m) / s

x = 72

Zscore = (72 - 66) / 3

Zscore = 6/3

= 2

P(Z < 2). = 0.9772

Between 60 and 72

0.9772 - 0.0228 = 95.44

c) In a particular year there are 25 horses running in the Melbourne Derby. How many of these would you expect to have a height of less than 63 inches?

Zscore = ( x - m) / s

x = 63

Zscore = (63 - 66) / 3

Zscore = - 3/3

= - 1

P(Z < - 1) = 0.1587

0.1587 * 25 = 3. 967 = 4

5 0

3 years ago

Select True or False for each statement.

ra1l [238]

Part one, false. part two true

3 0

3 years ago

Read 2 more answers

Researchers have noted a decline in cognitive functioning as people age (Bartus, 1990). However, the results from other research

kolbaska11 [484]

Complete Question

The complete question is shown on the first uploaded image

Answer:

Yes the researcher can conclude that the supplement has a significant effect on cognitive skill

$d = 0.5778$

The result of this hypothesis test shows that there is sufficient evidence to that the supplement had significant effect.The measure of effect size is large due to the large value of Cohen's d (0.5778 > 0.30 )

Step-by-step explanation:

From the question we are told that

The sample size is n=16

The sample mean is $M = 50.2$

The standard deviation is $\sigma = 9$

The population mean is $\mu = 45$

The level of significance is $\alpha = 0.05$

The null hypothesis is $H_o \mu =45$

The alternative hypothesis is $H_a \mu \ne 45$

Generally the test statistics is mathematically represented as

$z = \frac{M - \mu}{\frac{\sigma}{\sqrt{n} } }$

=> $z = \frac{50.2 - 45}{\frac{9}{\sqrt{16} } }$

=> $z = 2.31$

Generally the p-value is mathematically represented as

$p-value = 2 * P(Z > z )$

$p-value = 2 * P(Z > 2.31 )$

From the z-table

$P(Z > 2.31 ) = 0.010444$

=> $p-value = 2 * 0.010444$

=> $p-value = 0.021$

From the obtained values we see that $p-value < 0.05$

Decision Rule

Reject the null hypothesis

Conclusion

There is sufficient evidence to conclude that the supplement has a significant effect on the cognitive skill of elderly adults

Generally the Cohen's d for this study is mathematically represented as

$d = \frac{M - \mu}{\sigma }$

=> $d = \frac{50.2 -45}{9 }$

=> $d = 0.5778$

3 0

4 years ago

A garden snail moves 1/6 foot in 1/3 hour.<br><br> This is unit rates. Please explain your answer.

Alenkinab [10]

1/6 foot 0.16666667 ft
________ = ________________ = 0.50 ft/hr
1/3 hour 0.33333333 hr

A unit rate is identified as a rate with 1 in the denominator. Therefor, a garden snail moves 0.50 feet per 1 hour.

4 0

4 years ago