Answer:
- x = 30°, y = 45°
- w = 14√2, v = 7√2
Step-by-step explanation:
ΔABC
- BC/AB = sin x
- 12/24 = sin x
- 1/2 = sin x
- x = 30°
ΔDBC
- DC = BC - given
- ∠C = 90° - given
- ΔDBC is isosceles right triangle
∠BDC ≅ ∠DBC ⇒ y = 45°
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ΔMPN is right isosceles triangle ⇒ MN = PN√2 = 14√2
ΔMKP is right isosceles triangle ⇒ MK = KP
- v = 1/2MN = 1/2(14√2) = 7√2
Hi there!
We can begin by finding ∠VUY so we can solve for ∠UVY.
∠VUY is supplementary to ∠TUY, so:
180 = 144 + ∠VUY
∠VUY = 36°
In a triangle, angles sum up to 180°, so:
180 = 36° + 79° + m∠UVY
m∠UVY = 65°
Solve for m∠VYZ by comparing the angle to m∠UVY because the angles are alternating interior angles. Thus:
m∠UVY = m∠VYZ = 65°.
y = 2
A horizontal line, parallel to the x-axis has equation y = c
where c is the value of the y-coordinate the line passes through.
( - 2, 2) has y- coordinate of 2
equation of horizontal line is therefore y = 2
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