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balu736 [363]
3 years ago
14

The latte is covered with a milk foam heart is covering 55 square cm of the coffee, then what is the area of the coffee NOT cove

red in foam? The diameter is 4. Please explain how you got your answer
Mathematics
1 answer:
Marysya12 [62]3 years ago
6 0

Answer:

Step-by-step explanation:

The latte is what covered the coffee, Caffe latte is a coffee drink made with espresso and steamed milk, and this latte do form heart on the coffee, then we are told that the area of the latte heart is 55cm²

Then, space where latte is not form has a diameter 4cm

Then the radius is diameter divided by 2

r=d/2

r=4/2 =2

Then area of the circle which for the surface for the coffee is πr²

A=πr²

A=3.142×2²

A=12.568cm².

Area of coffee not covered is

55-12.568=42.432cm²

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On Monday, the temperature at 10 a.m. at Sam’s house was –6° Fahrenheit. The
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Step-by-step explanation:

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Memory module consists of 9 chips. The device is designed with redundancy so that it works even if one of its chips is defective
soldier1979 [14.2K]

Answer:

a) P[C]=p^n

b) P[M]=p^{8n}(9-8p^n)

c) n=62

d) n=138

Step-by-step explanation:

Note: "Each chip contains n transistors"

a) A chip needs all n transistor working to function correctly. If p is the probability that a transistor is working ok, then:

P[C]=p^n

b) The memory module works with when even one of the chips is defective. It means it works either if 8 chips or 9 chips are ok. The probability of the chips failing is independent of each other.

We can calculate this as a binomial distribution problem, with n=9 and k≥8:

P[M]=P[C_9]+P[C_8]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)\\\\P[M]=p^{8n}(p^{n}+9(1-p^n))\\\\P[M]=p^{8n}(9-8p^n)

c)

P[M]=(0.999)^{8n}(9-8(0.999)^n)=0.9

This equation was solved graphically and the result is that the maximum number of chips to have a reliability of the memory module equal or bigger than 0.9 is 62 transistors per chip. See picture attached.

d) If the memoty module tolerates 2 defective chips:

P[M]=P[C_9]+P[C_8]+P[C_7]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1+\binom{9}{7}P[C]^7(1-P[C])^2\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])+36P[C]^7(1-P[C])^2\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)+36p^{7n}(1-p^n)^2

We again calculate numerically and graphically and determine that the maximum number of transistor per chip in this conditions is n=138. See graph attached.

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4 years ago
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3 years ago
X<br> For f(x)=0.01(2) , find the average rate of change from x=3 to x=8.
NikAS [45]
  • Answer:

Option b. 0.496

  • Step-by-step explanation:

we know that

f(x)=0.01(2^{x})

The average rate of change is equal to

\frac{f(b)-f(a)}{b-a}

where

a=3

b=8

f(a)=f(3)=0.01(2^{3})=0.08

f(b)=f(8)=0.01(2^{8})=2.56

Substitute

\frac{2.56-0.08}{8-3}

\frac{2.48}{5}

0.496

3 0
3 years ago
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