3 years ago

Evaluate the following expression. 6^-3

Mathematics

2 answers:

tankabanditka [31]3 years ago

6 0

Answer:

$\frac{1}{216}$

Step-by-step explanation:

If you have any questions feel free to ask in the comments

Liono4ka [1.6K]3 years ago

5 0

Answer:

.0046, if you mean the -3 to be an exponent

Step-by-step explanation:

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Write an equation that describes each line in slope-intercept form. slope = 0, y-intercept = -3

patriot [66]

Answer:

y=0x+-3

Step-by-step explanation:

slope intercept form is y=mx+b

m is slope

b is y-intercept

y and x are points on a coordinate plane.

8 0

2 years ago

Give a third degree polynomial that has zeros of 13, 5i, and −5i, and has a value of −680 when x=3. Write the polynomial in stan

Vikki [24]

Answer:

$\dfrac{17x^3-221x^2+425x-5525}{9}\\$

Step-by-step explanation:

hello

we need to find something like, a being real

$a(x-13)(x-5i)(x+5i)$

with a so that

$a(3-13)(3-5i)(3+5i)=-680\\\\a(-10)(3^2-(5i)^2)= -10(9+25)a=-360a=-680\\ a = \dfrac{680}{360}=\dfrac{17*40}{9*40}=\dfrac{17}{9}$

so the third degree polynomial that we are looking for is

$\dfrac{17}{9}(x-13)(x-5i)(x+5i)\\=\dfrac{17}{9}(x-13)(x^2+25)\\\\=\dfrac{17}{9}(x^3+25x-13x^2-13*25)\\\\\\=\dfrac{17}{9}(x^3-13x^2+25x-325)\\\\\\\\=\dfrac{17}{9}x^3-\dfrac{17*13}{9}x^2+\dfrac{17*25}{9}x-\dfrac{17*325}{9}\\=\dfrac{17}{9}x^3-\dfrac{221}{9}x^2+\dfrac{425}{9}x-\dfrac{5525}{9}\\$