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3 years ago

How to solve this ? I am not sure pls if you know the answer answer it I really neeed it for marks

Mathematics

1 answer:

xz_007 [3.2K]3 years ago

4 0

Answer:

L.S = R.S ⇒ Proved down

Step-by-step explanation:

Let us revise some rules in trigonometry

sin²α + cos²α = 1
sin2α = 2 sin α cosα
cscα = 1/sinα

To solve the question let us find the simplest form of the right side and the left side, then show that they are equal

∵ L.S = csc2α + 1

→ By using the 3rd rule above

∴ L.S = $\frac{1}{sin2\alpha}$ + 1

→ Change 1 to $\frac{sin2\alpha}{sin2\alpha}$

∴ L.S = $\frac{1}{sin2\alpha}$ + $\frac{sin2\alpha}{sin2\alpha}$

→ The denominators are equal, then add the numerators

∴ L.S = $\frac{1+sin2\alpha}{sin2\alpha}$

∵ R. S = $\frac{(sin\alpha+cos\alpha)^{2} }{sin2\alpha}$

∵ (sinα + cosα)² = sin²α + 2 sinα cosα + cos²α

∴ (sinα + cosα)² = sin²α + cos²α + 2 sinα cosα

→ By using the 1st rule above, equate sin²α + cos²α by 1

∴ (sinα + cosα)² = 1 + 2 sinα cosα

→ By using the 2nd rule above, equate 2 sinα cosα by sin2α

∴ (sinα + cosα)² = 1 + sin2α

→ Substitute it in the R.S above

∴ R. S = $\frac{1+sin2\alpha}{sin2\alpha}$

∵ L.S = R.S

∴ csc 2α + 1 = $\frac{(sin\alpha+cos\alpha)^{2} }{sin2\alpha}$

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Polynomial Roots Calculator :

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