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kotegsom [21]
3 years ago
11

Taree fourts of the 64 books were math books. determine the percent of the books that were math books.​

Mathematics
1 answer:
Volgvan3 years ago
4 0

Answer:  <em>75% - these are books on mathematics.</em>

Step-by-step explanation:

\dfrac{3}{4} \cdot 64 = 48\\

<em>64 - 100%</em>

<em>48  -  x%</em>

\dfrac{64}{100} =\dfrac{48}{x}\\\\x=\dfrac{48 \cdot 100}{64}  \\\\x=75 \%

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What is the range of the function represented by the table of values below?
Viefleur [7K]
The range is the interval of y values.
Smallest y values is -9 and the highest y values is 9.
So the range is -9 \leq y \leq 9
4 0
3 years ago
If the exponential parent function,
laila [671]

Answer: f(x) =3^{-x}-4

Step-by-step explanation:

Some transformations for a function f(x) are shown below:

If f(x)+k, the function is translated up "k" units.

If f(x)-k, the function is translated down "k" units.

If -f(x), the function is reflected across the x-axis.

If f(-x), the function is reflected across the y-axis.

Therefore, knowing those transformations and given the exponential parent function:

f(x) = 3^x

If it is reflected across the y-axis and the it is  translated down 4 units, we can determine that the resulting function is:

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6 0
3 years ago
Expand each expression
matrenka [14]

Answer:

Option B - \ln(\frac{4y^5}{x^2})=\ln 4+5\ln y-2\ln x

Step-by-step explanation:

Given : Expression \ln(\frac{4y^5}{x^2})

To find : Expand each expression ?

Solution :

Using logarithmic properties,

\ln (\frac{A}{B})=\frac{\ln A}{\ln B}=\ln A-\ln B

and \ln (AB)=\ln A+\ln B

Here, A=4y^5 and B=x^2

\ln(\frac{4y^5}{x^2})=\frac{\ln 4y^5}{\ln x^2}

\ln(\frac{4y^5}{x^2})=\ln 4y^5-\ln x^2

\ln(\frac{4y^5}{x^2})=\ln 4+\ln y^5-\ln x^2

Using logarithmic property, \logx^a=a\log x

\ln(\frac{4y^5}{x^2})=\ln 4+5\ln y-2\ln x

Therefore, option B is correct.

3 0
3 years ago
Read 2 more answers
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blagie [28]

Answer:

Step-by-step explanation:

Start box

180 = 89+42+x

180-89-42=x

49 = x

2nd box

180 = 84+58+x

180-84-58=x

38 = x

3rd box

180=74+2x

180-74=2x

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53 = x

4th box

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180-102=2x

78/2 = x

39 = x

4th box

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180-73-81=x

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5th box

180=2*54+x

180 - 2*54 = x

72 = x

6th box

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180-62=2x

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118/2=x

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7th box

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3 0
2 years ago
Question 5 (1 point)
Damm [24]

Answer:

36 and 49

Step-by-step explanation:

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5 0
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