All categories

3 years ago

Four students were discussing how to find the unit rate for a proportional relationship. Which method is valid?

Mathematics

1 answer:

vovangra [49]3 years ago

3 0

Answer:

The method that is valid in finding the unit rate for a proportional relationship is by:

Look at the graph of the relationship. Count the number of units up and the number of units to the right one must move to arrive at the next point on the graph. Write these two numbers as a fraction. The unit rate is the slope, which is the rise over run.

Step-by-step explanation:

You might be interested in

Find a coterminous angle between 0 and 2 pi for each given angle. 191pi/45

Sedaia [141]

Check the picture below.

let's recall that 2π is a full go-around or namely a revolution

$\bf \cfrac{191}{45}\implies \cfrac{45+45+45+45+11}{45}\implies \cfrac{45}{45}+\cfrac{45}{45}+\cfrac{45}{45}+\cfrac{45}{45}+\cfrac{11}{45} \\\\\\ 1+1+1+1+\cfrac{11}{45}\implies \stackrel{\textit{and this more}}{\underset{\textit{2 go-around}}{\underset{\uparrow }{2+2}+\stackrel{\downarrow }{\cfrac{11}{45}}}}$

5 0

3 years ago

Multiply the quotient " 16 and 2 by 2" write in two different ways

zzz [600]

16/2 times 2 =16, 2/2 times 16 = 16

4 0

3 years ago

Show that 1n^ 3 + 2n + 3n ^2 is divisible by 2 and 3 for all positive integers n.

Dmitry_Shevchenko [17]

Prove:

Using mathemetical induction:

P(n) = $n^{3}+2n+3n^{2}$

for n=1

P(n) = $1^{3}+2(1)+3(1)^{2}$ = 6

It is divisible by 2 and 3

Now, for n=k, $n > 0$

P(k) = $k^{3}+2k+3k^{2}$

Assuming P(k) is divisible by 2 and 3:

Now, for n=k+1:

P(k+1) = $(k+1)^{3}+2(k+1)+3(k+1)^{2}$

P(k+1) = $k^{3}+3k^{2}+3k+1+2k+2+3k^{2}+6k+3$

P(k+1) = $P(k)+3(k^{2}+3k+2)$

Since, we assumed that P(k) is divisible by 2 and 3, therefore, P(k+1) is also

divisible by 2 and 3.

Hence, by mathematical induction, P(n) = $n^{3}+2n+3n^{2}$ is divisible by 2 and 3 for all positive integer n.

3 0

3 years ago

Determine whether or not there is a congruence between △abc and △def. if there is such a congruence, then give the reason for it

Andru [333]

There is no congruence between the triangles based on the given information. In general, two sides and an angle not between them are insufficient to specify the triangle completely. In this case, the angles that are congruent are adjacent to non-corresponding sides, so even if SSA correspondence were sufficient to ensure congruence, it would not be sufficient in this case.

The appropriate choice is

... none

4 0

3 years ago

David found and factored out the GCF of the polynomial 80b4 – 32b2c3 + 48b4c. His work is below. GFC of 80, 32, and 48: 16 GCF o

BlackZzzverrR [31]

Answer: The correct statements are

The GCF of the coefficients is correct.

The variable c is not common to all terms, so a power of c should not have been factored out.

David applied the distributive property.

Step-by-step explanation:

GCF = Greatest common factor

1) GCF of coefficients : (80,32,48)

80 = 2 × 2 × 2 × 2 × 5

32 = 2 × 2 × 2 × 2 × 2

48 = 2 × 2 × 2 × 2 × 3

GCF of coefficients : (80,32,48) is 16.

2) GCF of variables :( $b^4,b^2,b^4$ )

$b^4$ = b × b × b × b

$b^2$ = b × b

$b^4$ =b × b × b × b

GCF of variables :( $b^4,b^2,b^4$ ) is $b^2$

3) GCF of $c^3$ and c: c is not the GCF of the polynomial. The variable c is not common to all terms, so a power of c should not have been factored out.

4) $80b^4-32b^2c^3+48b^4c$

$=16b^2(5b^2-2c^3+3b^2c)$

David applied the distributive property.

7 0

2 years ago

Read 3 more answers