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vfiekz [6]
2 years ago
9

Multiply:

Mathematics
2 answers:
hammer [34]2 years ago
8 0

Answer:

2\times \left(-21\right)\times \:7

<u> PEMDAS order of operations:</u>

<u />2\times \left(-21\right)=-2\times \:21=-42<u />

<u />=-42\times \:7<u />

<u />=-294<u />

<u>D) -294</u><u> is your answer</u>

<u>OAmalOHopeO</u>

umka2103 [35]2 years ago
5 0
Use pemdas order & that’ll get you to your answer which is D) -294
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Solve for x. Round to the nearest tenth, if necessary.
galben [10]

Answer:

15.4

Step-by-step explanation:

sin 17° = 4.5 /x

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= 15.4

6 0
2 years ago
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CALCULUS: For an object whose velocity in ft/sec is given by v(t) = sin(t), what is its distance, in feet, travelled on the inte
rodikova [14]

The linked answer is wrong because that integral gives you the net displacement of the object, not the total distance.

To get the distance, you have to integrate the speed (as opposed to velocity), which involves integrating the absolute value of the velocity function.

\mathrm{distance} = \displaystyle\int_1^5 |\sin(t)| \,\mathrm dt

By definition of absolute value,

|\sin(t)|=\begin{cases}\sin(t)&\text{for }\sin(t)\ge0\\-\sin(t)&\text{for }\sin(t)

Over this particular integration interval,

• sin(<em>t</em> ) ≥ 0 for 1 ≤ <em>t</em> < <em>π</em>, and

• sin(<em>t</em> ) < 0 for <em>π</em> < <em>t</em> ≤ 5

so you end up splitting the integral at <em>t</em> = <em>π</em> as

\mathrm{distance} = \displaystyle\int_1^\pi \sin(t)\,\mathrm dt + \int_\pi^5 (-\sin(t))\,\mathrm dt

Now compute the distance:

\mathrm{distance} = -\cos(t)\bigg|_1^\pi + \cos(t)\bigg|_\pi^5

\mathrm{distance} = -(\cos(\pi) - \cos(1)) + (\cos(5) - \cos(\pi))

\mathrm{distance} = -2\cos(\pi) + \cos(1) + \cos(5) \approx 2.82

making B the correct answer.

7 0
2 years ago
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6 0
3 years ago
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Ugo [173]

Answer:

It would be 54.

Step-by-step explanation:

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2 x 2 = 4

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4 0
3 years ago
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Papessa [141]
Using the factor label method, you would set up your ratio like so:8.7 gall *  \frac{4 qts}{1 gall}
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3 years ago
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