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Slav-nsk [51]
3 years ago
6

(x - 6)^2 - 5 = 0 Enter the solutions from least to greatest.

Mathematics
2 answers:
vladimir2022 [97]3 years ago
8 0

Answer:

\Large \boxed{ x=6 -\sqrt{5} \ \  \mathrm{or} \ \ x=6 + \sqrt{5}}

Step-by-step explanation:

(x - 6)^2 - 5 = 0

Adding 5 to both sides of the equation.

(x - 6)^2 =5

Taking the square root of both sides of the equation.

x-6 =\pm \sqrt{5}

Adding 6 to both sides of the equation.

x=6 \pm \sqrt{5}

lukranit [14]3 years ago
7 0

Answer:

x=6- sqrt(5)

x=6+ sqrt(5)

Step-by-step explanation:

(x - 6)^2 - 5 = 0

Add 5 to each side

(x - 6)^2 =5

Take the square root of each side

sqrt((x - 6)^2)  =± sqrt(5)

x-6 =  ± sqrt(5)

Add 6 to each side

x-6+6=6± sqrt(5)

x=6± sqrt(5)

from least to greatest

x=6- sqrt(5)

x=6+ sqrt(5)

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A bag contains eight yellow marbles, nine green marbles, three purple marbles, and five red marbles. Two marbles are chosen from
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Answer:

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Step-by-step explanation:

A bag contains eight yellow marbles, nine green marbles, three purple marbles, and five red marbles. So in total there are 25 marbles.

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Probability of getting red ball = P(R)=\dfrac{5}{25}

Probability that one marble is yellow and the other marble is red is,

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A rectangular poster is to contain 578 square inches of print. The margins at the top and bottom of the poster are to be 2 inche
lord [1]

Answer:

19 by 38

Step-by-step explanation:

The area of the poster, A=xy

Margin at both up and bottom is 2inches, at the right and left is 1 inch

Then we can say

(x-4)(y-2)= 578

Let us make y subject of the formula

(y-2)= 578/(x-4)

y=[ 578/(x-4)] + 2

If we substitute into the area A equation we have

A= x { [ 578/(x-4)] + 2}

A= 2x + (578x)/(x - 4)

If we differentiate we have

A'(x)= [2+578(x-4)+578x ]/ (x-4)^2

=[ 2(x-4)^2 + 578(x -4) + 578x ] / (x-4)^2

=[ 2(x^2 - 8x +16) + 578(x-4) + 578x ] /(x-4)^2

If we simplify this we have

=[ 2x^2 -16x +32+578x -578x - 2312]/ (x-4)^2

=( 2x^2 -16x - 2312) / (x-4)^2

At A'(x)= 0

= ( x^2 - 8x - 2312) / (x-4)^ =0

If we divide through by 2 we have

x^2 - 8x - 1156= 0

Solving the quadratic eqn( CHECK THE ATTACHMENT)

X= 38 or -30 then we choose the positive one, then x= 38

Then from area of the poster

A= (x-4)(y-2)= 578

Substitute 38 as value of x

(38-4)(y-2)= 578

34(y-2)=578

34y-68=578

34y=646

y=19

Hence dimensions of the poster is 19 by 38

CHECK THE ATTACHMENT FOR QUADRATIC SOLUTION

7 0
3 years ago
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