Answer:
I'm pretty sure it's B
Explanation:
If i'm wrong i'm sorry :(
Answer:
Explanation:
First, we are going to need the water specific volume at 15ºC: v=0.001001 
. The density '
' of the water is the inverse of the specific volume: 
First, consider the mass flow, which is related to the volumetric flow (density and velocity) and the area:
The area of each cross-section is:
(in square meters). Here, the radius was not used but the diameter, which means a division by 4 (2 squared).
From mass flow isolate the velocity and calculate it:
The work of the pump is calculated considering an energy balance on the pump:
Considering the isentropic process may give us the relation:
Applying that to the pump,
Multiplying it by the mass flow:
The work is negative because it is entering to the system, but the required is positive. (It is just a standard rule)
Answer:
0.01228 moles OH⁻
Explanation:
The reaction of H₂SO₄ with KOH is:
H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O
Thus, we need to determine the moles of H2SO4 and KOH that reacts:
<em>Moles H₂SO₄:</em>
0.02173L * (0.142mol/L) = 3.086x10⁻³mol
<em>Moles KOH:</em>
0.04893L * (0.377mol/L) = 0.01845 mol KOH
The moles of KOH that reacts are:
3.086x10⁻³mol H₂SO₄ * (2 mol KOH / 1 mol H₂SO₄) = 6.172x10⁻³ moles KOH
And will remain in solution:
0.01845 mol KOH - 6.172x10⁻³ moles KOH = 0.01228 moles of KOH =
<h3>0.01228 moles OH⁻</h3>
Answer:E. NH3 and CH3OH
Explanation:
NH3 and CH3OH are soluble in water and would give an homogenous solution.
A homogeneous solution is a type of solution with uniform properties and compositional proportion throughout the solution.
