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Ilia_Sergeevich [38]
3 years ago
9

A 2.00 L bottle of Dr Pepper contains 225 g of sucrose, C12H22O11. What is the molality of that solution?

Chemistry
1 answer:
Firdavs [7]3 years ago
6 0

Answer:

Molality = 0.33 mol/Kg

Explanation:

Given data:

Volume of solvent  = 2.00 L

Mass of solute = 225 g

Molality of solution = ?

Solution:

Formula:

Molality = Number of moles of solute / kg of solvent

Now we will calculate the moles of solute.

Number of moles = mass/ molar mass

Number of moles = 225 g/ 342.3 g/mol

Number of moles = 0.66 mol

Now we will calculate the Kg of solvent.

1 L = 1 Kg

2 L = 2 Kg

Molality = Number of moles of solute / kg of solvent

Molality = 0.66 mol  / 2 kg

Molality = 0.33 mol/Kg

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If 650. grams of C6H12O6 (FW 180.16) reacts with 650. grams of O2 (FW 32.00) in cellular respiration: C6H12O6 6 O2 --> 6 CO2
cestrela7 [59]

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<em>Moles C6H12O6:</em>

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<em>Moles O2:</em>

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As there are just 20.31 moles of O2,

<h3>O2 is limiting reactant</h3>
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