Answer:
1 9.9
2 4.95
3 12.375
Explanation:
To solve this problem, we basically need to write a balanced chemical equation:
Like all other hydrocarbons, benzene burns in oxygen to yield water and carbon iv oxide as the only products. A balanced chemical equation is given below:
2C6H6(l)+15O2(g)→12CO2(g)+6H2O(g)
Let’s now proceed to answer the questions.
A. Number of moles of carbon iv oxide produced
From the balanced chemical equation, we can see that one mole of benzene yielded 6 moles of carbon iv oxide.
This means 1.65 moles of benzene will yield: 6 * 1.65 = 9.9 moles of CO2
B. From the balanced equation, we can see that one mole of benzene yielded 3 moles of water. Hence, 1.65 moles will yield 1.65 * 3 = 4.95 moles of water
C. To find the number of moles of oxygen consumed, we can see that 2 moles of benzene consumed 15 moles of oxygen. 1.65 moles of benzene would thus consume 1.65 * 15/2moles = 12.375moles of oxygen
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The total number of protons and neutrons in an atom is called the mass number. You can find the mass numberfor any element. The mass number canbe found by rounding the average atomic mass to the nearest whole number.
as an example
6.25 is closer to 6 than 7 so it is 6
6. 50 is closer to 7 so it is 7
you have to look at the thenth digit. if the number is 4 or less you have to round it down
if the tenth digit is 5 or greather than you have to round it up.
Answer: 1 part is sulfuric acid is a catalyst
2 part is vanadium (V) oxide is a catalyst
Explanation:
The statement of the combined gas law for a fixed amount of gas is,
PV/T = constant
Here, the units of pressure and volume must be consistent and the temperature must be the absolute temperature (Kelvin or Rankine).
0.65 atm is equivalent to 494 mmHg
Using the equation:
(755 x 500) / (27 + 273) = (494 x V) / (-33 + 273)
V = 3396 ml = 3.4 liters