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Vsevolod [243]
3 years ago
8

Please help me. I need help

Chemistry
2 answers:
Doss [256]3 years ago
5 0

Answer:

they both collided is one i guess

Explanation:

Bad White [126]3 years ago
3 0
They both collided into it
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Explanation:

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Convert 6.35 grams of aluminum sulfate to moles​
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Answer:

There are 0.0186 moles of formula units in 6.35 grams of aluminum sulfate \rm Al_2(SO_4)_3.

Explanation:

What's the empirical formula of aluminum sulfate?

Sulfate is an anion with a charge of -2 per ion. When sulfate ions are bonded to metals, the compound is likely ionic.

Aluminum is a group III metal. Its ions tend to carry a charge of +3 per ion.

The empirical formula of an ionic compound shall balance the charge on ions with as few ions as possible.

The least common multiple of 2 and 3 is 6. That is:

  • Three sulfate ions \rm {SO_4}^{2-} will give a charge of -6.
  • Two aluminum ions \rm Al^{3+} will give a charge of +6.

Pairing three \rm {SO_4}^{2-} ions with two \rm Al^{3+} will balance the charge. Hence the empirical formula: \rm Al_2(SO_4)_3.

What's the mass of one mole of aluminum sulfate? In other words, what's the formula mass of \rm Al_2(SO_4)_3?

Refer to a modern periodic table for relative atomic mass data:

  • Al: 26.982;
  • S: 32.06;
  • O: 15.999.

There are

  • two Al,
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in one formula unit of \rm Al_2(SO_4)_3.

Hence the formula mass of \rm Al_2(SO_4)_3:

\underbrace{2\times 26.982}_{\rm Al} + \underbrace{3\times 32.06}_{\rm S} + \underbrace{12\times 15.999}_{\rm O} = \rm 342.132\;g\cdot mol^{-1}.

How many moles of formula units in 6.35 grams of \rm Al_2(SO_4)_3?

\displaystyle n = \frac{m}{M} = \rm \frac{6.35\;g}{342.132\;g\cdot mol^{-1}} = 0.0186\;mol.

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