How can you find the measure of the third angle of a triangle if the other two measures are known?

2 answers:

7 0

you would add up both of the other two measures and then subtract that by 180 since all triangles add up to 180 degrees

kolezko [41]2 years ago

6 0

Answer : If you add all three interior angle measures together in a triangle it will always equal 180°.. To find a third angle you will subtract the sum of the two given angles from 180Â°

Explanation: hope this helps

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Factor this trinomial.<br> x^2-3x-4

oee [108]

(x-4)(x+1)

you’re welcome!

3 0

2 years ago

he graph represents function 1, and the equation represents function 2: A coordinate plane graph is shown. A horizontal line is

Reika [66]

Answer:

The answer is 2

Step-by-step explanation:

Rate of change of function is given by :

$\frac{(f(x_{2})-f(x_{1}))}{x_{2}-x_{1}}$

For function y = 6,

rate of change =

$=\frac{(f(x_{2})-f(x_{1}))}{x_{2}-x_{1}}\\=\frac{6-6}{x_{2}-x_{1}}\\=0$

because the function is independent of x.

For function y = 2·x + 7,

rate of change =

$=\frac{(f(x_{2})-f(x_{1}))}{x_{2}-x_{1}}\\=\frac{2\cdot x_{2}+7-2\cdot x_{1}-7}{x_{2}-x_{1}}\\=\frac{2\cdot x_{2}-2\cdot x_{1}}{x_{2}-x_{1}}\\=\frac{2\cdot (x_{2}-x_{1})}{x_{2}-x_{1}}\\=2$

So, the rate of change of 2 is greater than rate of change of function 1 by 2 - 0 = 2.

8 0

2 years ago

A friend has a 82% average before the final exam for a course. That score includes everything but the final, which counts for 30

Damm [24]

So you want to set up an equation for a weighted average. You know the final is 30% of the grade, so everything else is 70%. This gives you:

(Final)(.30) + (other grades)(.70) = course grade

The best grade the student can get would be if they get a hundred on the final, since that’s the best score you can make on the final. Then,

(100)(.30) + (82)(.70) = course grade
30 + 57.4 = course grade = 87.4 Which, If you round, the student would get an 87.

For the last part, we use the same equation, just filling in different parts.

(Final)(.30) + (other grades)(.70) = course grade

This time, we don’t know the grade for the final, but we know the course grade.

(Final)(.30) + (82)(.70) = 75
(Final)(.30) + 57.4 = 75
(Final)(.30) = 17.6
Final = (17.6)/(.30)
Final = 58.667 Which is approx a 59.

4 0

2 years ago

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stiks02 [169]

We're given

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