I worked it out and got this x=6
The first one because it the x coordinate does not continually grow (you have two answers for 1 as well as 2)
The perimeter doesn't tell you the area, and neither of them
can be calculated by knowing the other one.
Check this out:
Dimensions Perimeter Area .
1 by 38 78 38 square feet
2 by 37 78 74 square feet
3 by 36 78 108 square feet
5 by 34 78 170 square feet
10 by 29 78 290 square feet
15 by 24 78 360 square feet
17 by 22 78 374 square feet
19 by 20 78 380 square feet
19.5 by 19.5 78 380.25 square feet
Nine same perimeters, nine different areas !
Here's one more ... a long skinny one:
1 inch by 38ft 11in Perimeter = 78 ft. Area = 3.24 square feet.
Answer:
MC = 4.5cm
Step-by-step explanation:
Question:
Let the isosceles triangle ABC with AB = AC = 3 cm. if the mediator of the sides AC intersects with the side BC in M and the perimeter of the triangle AMC = 12 cm. Calculate MC.
Solution:
Find attached the diagram used in solving the question.
Given:
∆ABC is an isosceles triangle (two sides and angles are equal)
AB = BC = 3cm
Perimeter of ∆AMC = 12cm
From the diagram, M cuts AC at the the middle.
AD = CD = AC/2 = 3/2
Perimeter of Right angled ∆AMD = AM + AD + MD
= 3/2 + AM +MD
Perimeter of Right angled ∆CMD =CM + CD + MD
= 3/2 + CM +MD
Right angled ∆AMD = Right angled ∆CMD
CM = AM
Therefore ∆AMC is an isosceles triangle
CM = AM (two sides of an isosceles triangle are equal)
Let CM = AM = x
Perimeter of ∆AMC = AM + CM + AC
12 = x + x + 3
12 = 2x + 3
2x = 12-3
2x = 9
x = 9/2 = 4.5
CM = AM = 4.5cm
MC = CM = 4.5cm