The perimeter of a rectangle is <u>length + length + width + width</u>.
We know that the length of a rectangle is 3cm more than its width, which gives us the equation: (l for length and w for width)
l = 3 + w
We also know that the perimeter of the rectangle is 98cm, which gives us the equation:
98 = 2l + 2w (equation for perimeter of a rectangle as noted above)
We can divide both sides of this equation by 2 to get:
49 = l + w
Now we'll stick l = 3 + w into the above equation, which gives us:
49 = 3 + w + w
which simplifies to 49 = 3 + 2w.
Now we'll subtract 3 from both sides:
49 - 3 = 46
3 + 2w - 3 = 2w
which gives us 46 = 2w.
Dividing both sides by 2 gives us 23 = w.
Substituting w = 23 into the equation l = 3 + w gives us:
l = 3 + 23
l = 26cm.
Let's check our answer. 26cm is 3cm more than 23cm. 26cm + 26cm + 23cm + 23cm gives us 98cm. The length is 26cm and the width is 23cm.
Simply subtract 8.72 from 20.08 and you get the answer which is 11.36$
Answer:
|x y 1|
|7 -3 1| = 0
|4 -8 1|
x*(-3*1 - (-8)*1) - y*(7*1 - 4*1) + 1*(7*-8 - 4*-3) = 0
5x - 3y - 44 = 0
Step-by-step explanation:
Hi !
the answer is 5y+4
please let me know if im wrong (:
Answer:
59m
Step-by-step explanation:
No of passenger cars in the train = 6
length of each passenger cars = 18m
total length of 6 passenger cars = 18 * 6 = 108 m
length of caboose = 10m
total length of train when caboose is included = 108 m + 10 m = 118m
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Let the length of truck be X m
given that length of train is twice of length of truck = 2*X
but length of train as found above is 118 m
this implies
2X = 118
X = 118/2 = 59m
Therefore length of truck is 59m
