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3 years ago

The importance of reproduction??

2 answers:

5 0

I don’t understand the question completely, but reproduction in any case is important because it makes more of the product

Xelga [282]3 years ago

3 0

Answer:

<h3>The main significance of reproduction is to maintain continuity of species. It also helps in studying evolution as sexual reproduction results in variation among the species.</h3>

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find the activity coefficient of h , in a solution containing 0.010 m hcl plus 0.040 kclo4. what is the ph of the solution?

Lisa [10]

The activity coefficient of h is 0.05

The ph of the solution is 2.08

To find the activity coefficient, apply the concept of ionic equilibrium

h( activity coefficient)= 1/2CZ²

C is the concentration of species

Z is the charge on individual species

h= 1/2( 0.01 x1²+ 0.04x (-1)²+0.01 x1²+0.04x (-1)²)

h= 0.05

For the pH of the solution, apply the formula

pH= -log( H⁺x0.83)

pH = - log(0.01x0.83)

= 2.08

To learn more about the pH of the solution, visit brainly.com/question/26767292

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1 year ago

Which is a mixture?

Rama09 [41]

Potassium and chlorine

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4 years ago

Read 2 more answers

Element X

dedylja [7]

Element x is Silicon

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3 years ago

Italian dressing contains olive oil and vinegar, which will separate out from each other if left to sit. This makes the dressing

OleMash [197]

Italian salad dressing would be a suspension

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3 years ago

What is the mass of a sample of metal that is heated from 58.8°C to 88.9°C with a

Vadim26 [7]

Answer:

$\boxed {\boxed {\sf 333 \ grams}}$

Explanation:

We are asked to find the mass of a sample of metal. We are given temperatures, specific heat, and joules of heat, so we will use the following formula.

$Q= mc \Delta T$

The heat added is 4500.0 Joules. The mass of the sample is unknown. The specific heat is 0.4494 Joules per gram degree Celsius. The difference in temperature is found by subtracting the initial temperature from the final temperature.

ΔT= final temperature - initial temperature

The sample was heated from 58.8 degrees Celsius to 88.9 degrees Celsius.

ΔT= 88.9 °C - 58.8 °C = 30.1 °C

Now we know three variables:

Q= 4500.0 J
c= 0.4494 J/g°C
ΔT = 30.1 °C

Substitute these values into the formula.

$4500.0 \ J = m (0.4494 \ J/g \textdegree C)(30.1 \textdegree C)$

Multiply on the right side of the equation. The units of degrees Celsius cancel.

$4500.0 \ J = m (13.52694 J/g)$

We are solving for the mass, so we must isolate the variable m. It is being multiplied by 13.52694 Joules per gram. The inverse operation of multiplication is division, so we divide both sides by 13.52694 J/g

$\frac {4500.0 \ J }{13.52694 J/g}= \frac{m (13.52694 J/g)}{13.52694 J/g}$

The units of Joules cancel.

$\frac {4500.0 \ J }{13.52694 J/g}= m$

$332.6694729 \ g =m$

The original measurements have 5,4, and 3 significant figures. Our answer must have the least number or 3. For the number we found, that is the ones place. The 6 in the tenth place tells us to round the 2 up to a 3.

$333 \ g \approx m$

The mass of the sample of metal is approximately 333 grams.

8 0

3 years ago