<span>12 in = 1 ft. I hope u find this helpful</span>
Answer:
<em>C. 2.00 x 1023 molecules</em>
Explanation:
Given , the pressure , volume and temperature are same in both cases.
From the ideal gas equation,
P V = n R T
where n= no. of moles = given weight ÷ atomic weight
And 6.023 x 10^23 molecules of ammonia(NH3), weigh 17g ( 14 + 3(1 ))
So we have
P V = ((2.00 x 10^23)/(6.023 x 10^23)) x R T
Similarly, say <em>n</em> molecules of argon gas (Ar) are in an identical container.
So the gas equation would be
P V = ( n / 6.023 x 10^23 ) x R T
Because, atomic weight of Argon is beared by 6.023 x 10^23 molecules.
dividing these two equations, we get
n = 2.00 x 10^23 molecules
Answer: Option D is correct.
Explanation: Equation given by de Broglie is:

where,
= wavelength of the particle
h = Planck's constant
m = mass of the particle
v = velocity of the particle
In option A, football will have some mass and is moving with a velocity of 25 m/s, hence it will have some wavelength.
In Option B, unladen swallow also have some mass and is moving with a velocity of 38 km/hr, hence it will also have some wavelength.
In Option C, a person has some mass and is running with a velocity of 7 m/hr, hence it will also have some wavelength.
As, the momentum of these particles are large, therefore the wavelength will be of small magnitude and hence, is not observable.
From the above, it is clearly visible that all the options are having some wavelength, so option D is correct.
Answer:
i. Molar mass of glucose = 180 g/mol
ii. Amount of glucose = 0.5 mole
Explanation:
<em>The volume of the glucose solution to be prepared</em> = 500 
<em>Molarity of the glucose solution to be prepared</em> = 1 M
i. Molar mass of glucose (
) = (6 × 12) + (12 × 1) + (6 × 16) = 180 g/mol
ii.<em> mole = molarity x volume</em>. Hence;
amount (in moles) of the glucose solution to be prepared
= 1 x 500/1000 = 0.5 mole
Lattice energy is the amount of energy expelled when the solid is disintegrated into ions. For example, the solid is Sodium Chloride. In ionic form, that would consist of sodium and chlorine ions.The solid with a smaller lattice energy would be easily disrupted, hence, when a solvent is incorporated, the solid becomes solvated ions.