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3 years ago

5x + 3y + 7x3 - 2y - 4x2

Mathematics

2 answers:

Leno4ka [110]3 years ago

8 0

<h3>Answer: 5x + 3y + 7x3 - 2y - 4x2</h3>

Step-by-step explanation:

5x + 3y + 7x3-2y-4x2

5x+3y+21-2y-4x2

5x+3y+21-2y-8

5x+3y+13-2y

5x+3y +13-2y

5x+1y+13

5x+y+13

Multiply the numbers
Multiply the numbers
Subtract the numbers
Combine like terms
Multiply by 1
Solution

And I hoped this helps!

blsea [12.9K]3 years ago

7 0

Answer:

7x^3 - 4x^2 + 5x + y

Step-by-step explanation:

combine like terms! :)

hope i helped you.

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Which expresión represents, five times the quotient of two numbers?

MAXImum [283]

Let the numbers be m and n. Then "five times the quotient of two numbers" would be 5m/n.

6 0

3 years ago

Which statement correctly compares the mean number of students for the data in the plots?

satela [25.4K]

Answer:

"There are about 2 more students in each class at Oak Middle School than at Poplar Middle School."

Step-by-step explanation:

We need to compute the mean for each.

Poplar Middle School:

Lets list the numbers

20,20,20,21,21,21,21,21,22,22,22,22,22,22,22,23,23,23,23,24

The average is sum of all divided by number of numbers, that will be:

435/20 = 21.75

Oak Middle School:

The numbers are:

20,21,21,22,22,23,23,23,23,24,24,24,25,25,26,26,27,27,28,29

The average is sum divided by number of numbers, that will be:

483/20 = 24.15

The difference in mean is:

24.15 - 21.75 = 2.4

We can say, that is about 2 more students in Oak Middle School, correct answer choice is "2nd answer choice" - "There are about 2 more students in each class at Oak Middle School than at Poplar Middle School."

7 0

3 years ago

5 watermelons 6 cantaloupes cost $54. 4 watermelons and 8 cantaloupes $56. how much is a cantaloupe

GREYUIT [131]

Answer:

A cantaloupe costs $4

Step-by-step explanation:

Watermelons = W

Cantaloupes = C

Write given statements as equations

5W + 6C = 54

4W + 8C = 56

Simplify the second equation

4W + 8C = 56

Subtract 8C from both sides of the equation

4W = 56 - 8C

Divide both sides of the equation by 4

W = 14 - 2C

Substitute into second equation

5W + 6C = 54

5(14 - 2C) + 6C = 54

Multiply 5(14 - 2C)

70 - 10C + 6C = 54

Add -10C + 6C

70 - 4C = 54

Add 4C to both sides of the equation

70 = 54 + 4C

Subtract 54 from both sides of the equation

16 = 4C

Divide both sides of the equation by 4

C = 4

A cantaloupe costs $4

5W + 6(4) = 54

Multiply 6(4)

5W + 24 = 54

Subtract 24 from both sides of the equation

5W = 30

Divide both sides of the equation by 5

W = 6

A cantaloupe costs $4

A watermelon costs $6

Hope this helps :)

8 0

3 years ago

Use the quadratic formula to solve the quadratic equation x2 − 8x − 4 = 0.

mixas84 [53]

Hello here is a solution :
x² − 8x − 4 = 0.
quadratic equation ax²+bx+c = 0 when : a=1 and b= -8 and c = -4
discriminant : d = b²-4ac d= (-8)²-4(1)(-4) =64+16 =70
x= (-b-rot(d))/2a x'= (-b+rot(d))/2a .......conrinu

4 0

2 years ago

Segment BD is an altitude of triangle ABC. Find the area of the triangle. Triangle ABC with altitude BD is shown. Point A is at

pogonyaev

Where's the "triangle with alt. BD?" This problem can be solved without the diagram, but the solution would be easier with it.

BD is the altitude. Find the length of BD by finding the dist. between (-1,4) and (2,4); it is 2-(-1), or 3. |BD| = 3.

I've graphed the triangle myself and have found that the "base" of the triangle is the vertical line thru (2,1) and (2,6); its length is 6-1, or 5.

Thus, the area of this triangle is A = (b)(h) / 2, or A = (5)(3) / 2 = 10/3 square inches.

7 0

3 years ago

Read 2 more answers