The complete equation is x^2 - 4x + (-2) = (-2)^2
<h3>How to complete the equation?</h3>
The equation is given as:
x^2 - 4x + __ = (__)^2
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Take the coefficient of x
k = -4
Divide by 2
k/2 = -4/2
k/2 = -2
Square both sides
(k/2)^2 = (-2)^2
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Add the result of the above computation to both sides of x^2 - 4x + __ = (__)^2
So, we have:
x^2 - 4x + (-2) = (-2)^2
Hence, the complete equation is x^2 - 4x + (-2) = (-2)^2
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Let x + 1.5 be length of segment above left hand
Let 2x be length of segment below left hand
15 = x + 1.5 + 2x
15 = 3x + 1.5
15 - 1.5 = 3x
13.5 = 3x
13.5/3= 3x/3
4.5 = x
x = 4.5
This is the length above the left hand.
2x must be then 4.5*2 = 9 foot
This is the length below the left hand.
Checking
4.5 + 9 + 1.5 = 15 foot
Adding length below left hand & length of left hand to right hand:
9 + 1.5 = 10.5
The right hand is hence 10.5 foot far up the pole.
Answer:
C. 1 and 7
Step-by-step explanation:
<span>75.146523539 is the answer</span>
Answer:
The approximate probability that 10 squared centimeters of dust contains more than 10110 particles is 0.1357
Step-by-step explanation:
For a sample of 10 sqaured centimeters of dust, the total amount of asbestos particles has a Poisson distribution with a mean of 1000/1 * 10 = 10000.
We will approximate this probability to a normal distribution. The variance is also 10000 (because it is poisson), therefore the standard deviation is √10000 = 100. Lets call X the distribution, and W its standarization, given by
We have
Where 
is the cummulative distribution function of a standard normal distribution. The values of are well known and they can be found in the attached file.
We conclude that the approximate probability that 10 squared centimeters of dust contains more than 10110 particles is 0.1357.
