Hello,
Answer A
s(x)=3x-7
s(2t-4)=3*(2t-4)-7=6t-12-7=6t-19
Answer:

Step-by-step explanation:
we have
<em>The equation of the first line</em>
------> equation A
<em>The equation of the second line</em>
------> equation B
Solve the system of equations by elimination
Multiply equation A by -4 both sides
--------> equation C
Adds equation B and equation C

<em>Find the value of x</em>
substitute the value of y


Multiply by 3 both sides


therefore
The solution to the system of equations is the point 
Answer: Right triangle
Step-by-step explanation: There is a 90 degree angle diagonal from the hypotenuse
Make a horizontal line on the paper. You may draw arrows on the ends of the line to indicate it is a number line that continues past your data sample.
Put the label "X" to the right of the line to indicate the x axis.
Mark the center of the line with a vertical tick mark and label it 0. This is the origin of the graph.
Make equally spaced tick marks on the rest of the x axis. For this example you should label the tick marks from 1 to 10 on the right side of the 0.