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Leokris [45]
3 years ago
6

SOMEONE HELP ME PLEASE AS SOON AS POSSIBLE

Mathematics
1 answer:
Archy [21]3 years ago
7 0

Answer:

<h2>C</h2>

Step-by-step explanation:

Following the Pythagoras theorem

SohCahToa

meaning Soh - sine , opposite , hypotenuse

Cah - cos , adjacent , hypotenuse

Toa - tan , opposite ,adjacent

so , therefore sin B is correct,

  1. tan B is also correct,
  2. cos B is incorrect , the correct answer suppose to be 6/10
  3. cos C is correct ,

Hope this is helpful,

Have a nice day . :-)

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What is the minimum number of binary bits needed to represent each of the following unsigned decimal integers? a. 65
professor190 [17]

Answer: N >/= 7 bits

Minimum of 7 bits

Step-by-step explanation:

The minimum binary bits needed to represent 65 can be derived by converting 65 to binary numbers and counting the number of binary digits.

See conversation in the attachment.

65 = 1000001₂

65 = 7 bits :( 0 to 2^7 -1)

The number of binary digits is 7

N >/= 7 bits

7 0
3 years ago
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Brainliest If Correct
natta225 [31]

Answer:

52

Step-by-step explanation:

Messed up, 292+52=240, I hope it’s correct for you,  I have Alzheimer, I hope is correct for you!

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3 years ago
The box which measures 70cm X 36cm X 12cm is to be covered by a canvas. How many meters of canvas of width 80cm would be require
grigory [225]

Answer:

142.2 meters.  

Step-by-step explanation:

We have been given that a box measures 70 cm X 36 cm X 12 cm is to be covered by a canvas.      

Let us find total surface area of box using surface area formula of cuboid.

\text{Total surface area of cuboid}=2(lb+bh+hl), where,

l = Length of cuboid,

b = Breadth of cuboid,

w = Width of cuboid.

\text{Total surface area of box}=2(70\cdot36+36\cdot 12+12\cdot 70)

\text{Total surface area of box}=2(2520+432+840)

\text{Total surface area of box}=2(3792)

\text{Total surface area of box}=7584

Therefore, the total surface area of box will be 7584 square cm.  

To find the length of canvas that will cover 150 boxes, we will divide total surface area of 150 such boxes by width of canvass as total surface area of canvas will also be the same.

\text{Width of canvas* Length of canvass}=\text{Total surface area of 150 boxes}

80\text{ cm}\times\text{ Length of canvass}=150\times 7584\text{cm}^2

\text{ Length of canvass}=\frac{150\times 7584\text{ cm}^2}{80\text{ cm}}

\text{ Length of canvass}=\frac{1137600\text{ cm}^2}{80\text{ cm}}

\text{ Length of canvass}=14220\text{ cm}

Let us convert the length of canvas into meters by dividing 14220 by 100 as 1 meter equals to 100 cm.

\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}

\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}

\text{ Length of canvass}=\frac{14220\text{ cm}}{100}\times\frac{m}{cm}

\text{ Length of canvass}=142.20\text{ m}

Therefore, 142.2 meters of canvas of width 80 cm required to cover 150 such boxes.

5 0
4 years ago
If x/5 +6=-14,then x=
Otrada [13]

Answer: x= -100

Step-by-step explanation:

X/5=-14-6

X/5=-20

X=-100

3 0
3 years ago
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What is the equation of the line in slope intercept form? I WILL GIVE BRAINLY
irina [24]

Answer:

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Hope this helps!

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4 years ago
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