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3 years ago

ABCD Is a parallelogram if m

Mathematics

2 answers:

Viefleur [7K]3 years ago

7 0

Step-by-step explanation:

ABC+DAB=180

DAB=180-115

DAB= 65

m<3+m<4=65

m<3=65-m<4

You have been given 4 degrees there, but it has not fallen. The answer is either A or B. Subtracting the conditional degree from 65. Find 3.

VLD [36.1K]3 years ago

7 0

Answer:

...

Step-by-step explanation:

m<4=30

180-115=65

65-30= 35 , so m<3= 35

180- 150 = 30

so m<1= 30

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Pls help me solve this

NISA [10]

Answer:

$50

Step-by-step explanation:

12 x 30 = 360

960 - 360 = 600

600/12 = 50

3 0

2 years ago

Read 2 more answers

A high school student has started a new job. He plans to save $1 the first week, $2 the second week, $4 the third week, and $8 t

Mama L [17]

If you already know that you have . . .

1$ after week 1
2$ after week 2
4$ after week 3
8$ after week 4

. . . You can then tell that every week the money you save doubles (times 2)

So to continue . . . .
16$ after week 5
32$ after week 6
64$ after week 7
128$ after week 8
256$ after week 9
512$ after week 10

You will then know that after ten weeks u will have 512$ which is answer choice D.

Hope this helps! :)

3 0

3 years ago

Read 2 more answers

The height of a tennis ball tossed into the air is modeled by h(x) = 40x â€" 16x 2, where x is elapsed time in seconds. During w

egoroff_w [7]

The time interval x >0.5 and x > 2.04 will the tennis ball be at least 15 feet above the ground.

Given that,

The height of a tennis ball tossed into the air is modeled by,

$\rm h(x) = 40x - 16x^2$

Where x is elapsed time in seconds.

We have to determine,

During what time interval will the tennis ball be at least 15 feet above the ground?

According to the question,

The height of a tennis ball tossed into the air is modeled by,

$\rm h(x) = 40x - 16x^2$

Where x is elapsed time in seconds.

Then,

When the tennis ball be at least 15 feet above the ground,

$h(x) = 15$

Substitute the value of h(x) in the equation,

$\rm h(x) = 40x - 16x^2\\\\ 15 = 40x - 16x^2\\\\ 16x^2-40x+15=0$

Factorize the equation for finding the time interval will the tennis ball be at least 15 feet above the ground is,

$\rm 16x^2-40x+15= 0\\\\x = \dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\x = \dfrac{-(-40)\pm \sqrt{(-40)^2-4 \times 16 \times 15}}{2 \times 16}\\\\x = \dfrac{-(-40)\pm \sqrt{1600- 960}}{32}\\\\x = \dfrac{40\pm \sqrt{640}}{32}\\\\x = \dfrac{40 + 25.29}{32} \\\\x = \dfrac{40 + 25.29}{32} \ and \ x = \dfrac{40 - 25.29}{32}\\\\x = \dfrac{65.29}{32} \ and \ x = \dfrac{14.71}{32}\\\\x = 2.04 \ and \ x = 0.45$