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Andrei [34K]
3 years ago
10

Graph the quadratic inequality of y>x^2+6x+6

Mathematics
1 answer:
Lorico [155]3 years ago
3 0

Answer:

Step-by-step explanation:

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HELPPPPPPPPPPPPPPPPPP PLEASEEEEEEEEE YOU ARE SAVING MY LIFE IF YOU HELP ME !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Sladkaya [172]

Answer:

C. 8x - 16

D.  x^2 + 6x + 8

A. 2 (x + 3)

B. 7(2 - x)

C. -8x

D. 7x

Step-by-step explanation:

c.

To solve this problem, first, one must distribute, multiply every term inside the parenthesis by the term outside,

2(4x - 8)

=(2)(4x) + (2)(-8)

= 8x - 16

d.

To solve this problem, distribute, multiply every term inside one parenthesis by every term in the other, the combine like terms,

(x + 4)(x + 2)

= (x)(x) + (4)(x) + (2)(x) + (4)(2)

= x^2 + 4x + 2x + 8

= x^2 + 6x + 8

a.

Factor, write the given expression as the product of two expressions. Take out a common factor that both terms have,

2x + 6

= 2(x + 3)

b.

Factor this expression, take out a common factor, and rewrite the expression as the product of two other expressions,

14 - 7x

7(2 - x)

c.

Combine like terms,

2x - 10x

= -8x

d.

Combine like terms to solve this problem

3x + 4x

= 7x

4 0
3 years ago
Which number line model represents the sum of 1.25 + (-0.75) ?
sergeinik [125]

Answer:

Option c

Step-by-step explanation:

8 0
3 years ago
Change at least one number in the table so that it DOES represent a function.
almond37 [142]

Answer:

change 2 to 4

and 1 to 5

1 --> 5

2 --> 10

3 --> 15

4 --> 20

5 --> 24

Step-by-step explanation:

Function means you can have one input for evry one output

so you have to change the 2 and 1 to diffrent numbers like 4 and 5

so now evey imput has their own out put

befor input one it had 5 and 24

and input two had 10 and 20 but changing the number you get one for one

6 0
3 years ago
800,000 rounded to the nearest hundred thousand
8090 [49]
It would stay the same at 800,000 because there's nothing to show that it can be rounded.
7 0
3 years ago
PLEASE HURRY 50 POINTS Answer Both parts and I will reward Brainliest
vlabodo [156]

We have:

a_1=-3

and:

r=4

so:

$\sum\limits_{n=2}^5\,-3\cdot4^{n-1}=\sum\limits_{n=1}^5\,-3\cdot4^{n-1}-a_1=S_5-a_1=\frac{-3-(-3)\cdot 4^5}{1-4}-(-3)=

=\dfrac{-3-(-3)\cdot 1024}{-3}+3=\dfrac{-3(1-1024)}{-3}+3=1-1024+3=\boxed{-1020}

It is a finite sum, so it is convergent.

6 0
3 years ago
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