Air is mainly composed of N2 (78%), O2 (21%) and other trace gases. Now, the total pressure of air is the sum of the partial pressures of the constituent gases. The partial pressure of each gas, for example say O2, can be expressed as:
p(O2) = mole fraction of O2 * P(total, air) ----(1)
Thus, the partial pressure is directly proportional to the total pressure. If we consider a sealed container then, as the temperature of air increases so will its pressure. Based on equation (1) an increase in the pressure of air should also increase the partial pressure of oxygen.
6,200,0 is the answer to that
Answer:
Explanation:
- The formulae used in solving the problem ; ΔTf = i × Kf × m
- where ΔTf = depression in freezing point ,
- i = vant hoff factor 1 for non dissociable solutes ,
- Kf = freezing point constant for solvent
Appropriate substitution was done as shown in the attached file.
Maybe because meiosis have more chromosomes than mitosis but don't put that on there but that maybe it it because in class we have not went over that yet
